Bourbaki

Definition 3

Tag 0816, permanent. Cite it as [Bourbaki, Tag 0816].

Topological Vector Spaces, chapter V, § 4. Some classes of operators in hilbertian spaces

Let EE and FF be two hilbertian spaces. A mapping u∈L(E;F)u \in \mathscr{L}(E; F) is said to be partially isometric if ∥u(x)∥=∥x∥\|u(x)\| = \|x\| for all xx belonging to the initial subspace of uu.

Let u∈L(E;F)u \in \mathscr{L}(E; F) and let NN be its kernel and II its image. To say that uu is partially isometric is the same as saying that the linear mapping u~:E/N→I\tilde{u}: E/N \to I deduced from uu is isometric (V, p. 13). Then the subspace II of FF is complete, hence closed, and is the final subspace of uu. Consequently, uu induces a hilbertian space isomorphism from the initial subspace of uu onto its final subspace.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.