Bourbaki

Definition 5

Tag 081D, permanent. Cite it as [Bourbaki, Tag 081D].

Topological Vector Spaces, chapter V, § 4. Some classes of operators in hilbertian spaces

Let E be a hilbertian space and let u∈L(E)u \in \mathscr{L}(E). We say that u is hermitian if u∗=uu^* = u.

Let H(E)\mathscr{H}(E) denote the set of all hermitian elements of L(E)\mathscr{L}(E); this is a vector subspace of the vector space L(E)[R]\mathscr{L}(E)_{[\mathbf{R}]} over R\mathbf{R} which is deduced from L(E)\mathscr{L}(E) by restricting the scalars.

To each u∈L(E)u \in \mathscr{L}(E), we associated (V, p. 16, cor. 2) a sesquilinear form Φu:(x,y)↦⟨x∣u(y)⟩\Phi_u : (x, y) \mapsto \langle x|u(y)\rangle on E×EE \times E. We have

Φu∗(x,y)=Φu(y,x)‾(x,y in E); \Phi_{u^*}(x, y) = \overline{\Phi_u(y, x)} \quad (x, y \text{ in } E);

consequently, uu is hermitian if and only if the form Φu\Phi_u is hermitian. When K is C\mathbf{C}, it is enough to assume that Φu(x,x)=⟨x∣u(x)⟩\Phi_u(x, x) = \langle x|u(x)\rangle is real for all x∈Ex \in E (V, p. 2, Remark).

Let u∈L(E)u \in \mathscr{L}(E). We have seen (V, p. 16, cor. 2) that the norm of uu can be calculated by the formula

∥u∥=sup⁡∥x∥⩽1,∥y∥⩽1∣Φu(x,y)∣. \|u\| = \sup_{\|x\| \leqslant 1, \|y\| \leqslant 1} |\Phi_u(x, y)|.

When uu is hermitian, we have the following result :

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.