Bourbaki

Proposition 13

Tag 081L, permanent. Cite it as [Bourbaki, Tag 081L].

Topological Vector Spaces, chapter V, § 4. Some classes of operators in hilbertian spaces

— Let H(E)\mathscr{H}(E) be the set of all continuous hermitian endomorphisms of the hilbertian space EE. Let F\mathscr{F} be a non-empty, directed increasing and bounded subset of H(E)\mathscr{H}(E).

(i) The set F\mathscr{F} has an upper bound u0u_0 in H(E)\mathscr{H}(E); we have

⟨x∣u0(x)⟩=sup⁡u∈F⟨x∣u(x)⟩for allx∈E. \langle x|u_0(x)\rangle = \sup_{u \in \mathscr{F}} \langle x|u(x)\rangle \quad \text{for all} \quad x \in E .

(ii) The filter of sections of F\mathscr{F} converges to u0u_0 in the space L(E)\mathscr{L}(E) endowed with the topology of simple convergence.

Let Σ\Sigma be the filter of sections of F\mathscr{F}; for every u∈H(E)u \in \mathscr{H}(E), let Φu\Phi_u be the continuous hermitian form on EE defined by

Φu(x,y)=⟨x∣u(y)⟩. \Phi_u(x, y) = \langle x|u(y)\rangle .
Let
Ψu(x)=Φu(x,x) \Psi_u(x) = \Phi_u(x, x)
for u∈H(E)u \in \mathscr{H}(E) and x∈Ex \in E. By the polarization formulas (V, p. 2), we have
(19)4Φu(x,y)=Ψu(x+y)−Ψu(x−y)if K=R(20)4Φu(x,y)=Ψu(x+y)−Ψu(x−y)−iΨu(x+iy)+iΨu(x−iy)if K=C. \begin{align*} (19) \quad 4\Phi_u(x, y) &= \Psi_u(x+y) - \Psi_u(x-y) & \text{if } K = \mathbf{R} \\ (20) \quad 4\Phi_u(x, y) &= \Psi_u(x+y) - \Psi_u(x-y) - i\Psi_u(x+iy) + i\Psi_u(x-iy) & \text{if } K = \mathbf{C} . \end{align*}

For every x∈Ex \in E, the mapping u↦Ψu(x)u \mapsto \Psi_u(x) from into R\mathbf{R} is increasing and bounded, hence has a limit with respect to Σ\Sigma. By the preceding formulas, the limit

lim⁡u,ΣΦu(x,y)=Φ(x,y) \lim_{u,\Sigma} \Phi_u(x, y) = \Phi(x, y)
exists for every pair (x,y)(x, y) of elements of EE. It is clear that Φ\Phi is a hermitian form on EE. If v1∈Fv_1 \in \mathscr{F} and v2v_2 is a bound of F\mathscr{F}, the hermitian forms f1=Φ−Φv1f_1 = \Phi - \Phi_{v_1} and f2=Φv2−Φf_2 = \Phi_{v_2} - \Phi are positive; there exists a real number M≥0M \geq 0 such that
f1(x,x)+f2(x,x)=Φv2−v1(x,x)≤M∥x∥2, f_1(x, x) + f_2(x, x) = \Phi_{v_2 - v_1}(x, x) \leq M \|x\|^2,
hence
f1(x,x)≤M∥x∥2,f2(x,x)≤M∥x∥2(x∈E); f_1(x, x) \leq M \|x\|^2, \quad f_2(x, x) \leq M \|x\|^2 \quad (x \in E);
consequently the semi-norms x↦fi(x,x)1/2x \mapsto f_i(x, x)^{1/2} are continuous on EE. Since
f2−f1=Φv2+Φv1−2Φ, f_2 - f_1 = \Phi_{v_2} + \Phi_{v_1} - 2\Phi,
we conclude that x↦Φ(x,x)x \mapsto \Phi(x, x) is a continuous function on EE, and by formulas (19) and (20), that Φ\Phi is continuous on E×EE \times E. Therefore there exists (V, p. 16, cor. 2) an element u0u_0 of H(E)\mathscr{H}(E) such that Φ=Φu0\Phi = \Phi_{u_0}. Formula (18) is evidently satisfied, hence u0u_0 is the upper bound of F\mathscr{F} in H(E)\mathscr{H}(E). This proves (i).

We have, by construction

lim⁡u,Σ⟨x∣(u0−u)(x)⟩=0for all x∈E. \lim_{u,\Sigma} \langle x|(u_0 - u)(x)\rangle = 0 \quad \text{for all } x \in E.
Let v1∈Fv_1 \in \mathscr{F}; given a u∈Fu \in \mathscr{F} such that u≥v1u \geq v_1, let v=u0−uv = u_0 - u. If we apply the Cauchy-Schwarz inequality to the positive hermitian form Φv\Phi_v on EE, we get
∥v(x)∥4=∣Φv(v(x),x)∣2≤Φv(v(x),v(x))⋅Φv(x,x)=⟨v(x)∣v2(x)⟩⟨x∣v(x)⟩≤∥v∥3∥x∥2⟨x∣v(x)⟩≤∥u0−v1∥3∥x∥2⟨x∣v(x)⟩, \begin{align*} \|v(x)\|^4 &= |\Phi_v(v(x), x)|^2 \leq \Phi_v(v(x), v(x)) \cdot \Phi_v(x, x) \\ &= \langle v(x)|v^2(x)\rangle \langle x|v(x)\rangle \leq \|v\|^3 \|x\|^2 \langle x|v(x)\rangle \\ &\leq \|u_0 - v_1\|^3 \|x\|^2 \langle x|v(x)\rangle, \end{align*}
since ∥v∥≤∥u0−v1∥\|v\| \leq \|u_0 - v_1\| by V, p. 44, prop. 9. Then by (21) we get lim⁡u,Σ∥(u0−u)(x)∥=0\lim_{u,\Sigma} \|(u_0 - u)(x)\| = 0 for all x∈Ex \in E; which proves assertion (ii).

In particular, prop. 13 can be applied to the case of an increasing and bounded sequence (un)n∈N(u_n)_{n \in \mathbf{N}} of elements of H(E)\mathscr{H}(E). Then there exists an element vv of H(E)\mathscr{H}(E) characterized by

⟨x∣v(x)⟩=lim⁡n→∞⟨x∣un(x)⟩=sup⁡n∈N⟨x∣un(x)⟩(x∈E), \langle x|v(x)\rangle = \lim_{n \to \infty} \langle x|u_n(x)\rangle = \sup_{n \in \mathbf{N}} \langle x|u_n(x)\rangle \quad (x \in E),
and we have v(x)=lim⁡n→∞un(x)v(x) = \lim_{n \to \infty} u_n(x) for all x∈Ex \in E. Moreover, vv is the upper bound of the set of the unu_n in H(E)\mathscr{H}(E).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.