Bourbaki

Proposition 5

Tag 0898, permanent. Cite it as [Bourbaki, Tag 0898].

Functions of a Real Variable, chapter II, § 3. DERIVATIVES AND INTEGRALS OF FUNCTIONS DEPENDING ON A PARAMETER

Suppose that the partial derivative fα′(x,α)\mathbf{f}'_{\alpha}(x, \alpha) exists for all x∈Ix \in I and all α\alpha in an open neighbourhood VV of α0\alpha_0, and that, for all α∈V\alpha \in V, the map x↦fα′(x,α)x \mapsto \mathbf{f}'_{\alpha}(x, \alpha) is regulated on II. Under these conditions, if x↦fα′(x,α)x \mapsto \mathbf{f}'_{\alpha}(x, \alpha) converges uniformly on II to x↦fα′(x,α0)x \mapsto \mathbf{f}'_{\alpha}(x, \alpha_0) as α\alpha tends to α0\alpha_0, then the function g(α)=∫abf(t,α) dtg(\alpha) = \int_a^b \mathbf{f}(t, \alpha)\,dt admits a derivative, given by the formula (12), at the point α0\alpha_0.

Indeed, for every ε>0\varepsilon > 0 there exists by hypothesis an r>0r > 0 such that ∣α−α0∣≤r|\alpha - \alpha_0| \leq r implies ∥fα′(x,α)−fα′(x,α0)∥≤ε\| \mathbf{f}'_{\alpha}(x, \alpha) - \mathbf{f}'_{\alpha}(x, \alpha_0) \| \leq \varepsilon for any x∈Ix \in I. By props. 3 and 5 of I, p. 17 one has, for ∣α−α0∣≤r|\alpha - \alpha_0| \leq r (α≠α0\alpha \neq \alpha_0) and for all x∈Ix \in I

∥f(x,α)−f(x,α0)α−α0−fα′(x,α0)∥≤ε \left\| \frac{\mathbf{f}(x, \alpha) - \mathbf{f}(x, \alpha_0)}{\alpha - \alpha_0} - \mathbf{f}'_{\alpha}(x, \alpha_0) \right\| \leq \varepsilon

which proves the uniform convergence of f(x,α)−f(x,α0)α−α0\frac{\mathbf{f}(x, \alpha) - \mathbf{f}(x, \alpha_0)}{\alpha - \alpha_0} to fα′(x,α0)\mathbf{f}'_{\alpha}(x, \alpha_0) on I as α\alpha tends to α0\alpha_0 (remaining ≠α0\neq \alpha_0), and so establishes formula (12).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

Transcribed from the printed volume. Not translated.