Suppose that the partial derivativefα′(x,α)exists for allx∈Iand allαin an open neighbourhoodVofα0, and that, for allα∈V, the mapx↦fα′(x,α)is regulated onI. Under these conditions, ifx↦fα′(x,α)converges uniformly onItox↦fα′(x,α0)asαtends toα0, then the functiong(α)=∫abf(t,α)dtadmits a derivative, given by the formula (12), at the pointα0.
Indeed, for every ε>0 there exists by hypothesis an r>0 such that ∣α−α0∣≤r implies ∥fα′(x,α)−fα′(x,α0)∥≤εfor anyx∈I. By props. 3 and 5 of I, p. 17 one has, for ∣α−α0∣≤r (α=α0) and for all x∈I
α−α0f(x,α)−f(x,α0)−fα′(x,α0)≤ε
which proves the uniform convergence of α−α0f(x,α)−f(x,α0) to fα′(x,α0) on I as α tends to α0 (remaining =α0), and so establishes formula (12).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.