Bourbaki

Proposition 3

Tag 08BH, permanent. Cite it as [Bourbaki, Tag 08BH].

Functions of a Real Variable, chapter IV, § 1. EXISTENCE THEOREMS

On every compact interval with left (or right) endpoint t0 contained in J, with length less than r/(M + ε), there exists an approximate solution to within ε of equation (1), with values in S, and equal to x_0 at t_0.*

We suppose that t0t_0 is not the right-hand endpoint of J, and prove the proposition for intervals with left-hand endpoint t0t_0. Let M\mathscr{M} be the set of solutions of (1) to within ε\varepsilon, each of which takes values in S, is equal to x0x_0 at t0t_0, and is defined on a half open interval [t0,b[[t_0, b[ contained in J (the interval depending on the approximate solution under consideration). First we show that M\mathscr{M} is not empty. Let c be right limit of f(t,x0)f(t, x_0) at t0t_0; by lemma 1 (IV, p. 165) the function f(t,x0+c(t−t0))f(t, x_0 + c(t - t_0)) has a right limit equal to c at t0t_0, so the restriction of the function x0+c(t−t0)x_0 + c(t - t_0) to a sufficiently small half open interval [t0,b[[t_0, b[ will belong to M\mathscr{M}.

We order the set M\mathscr{M} by the relation "u is a restriction of v", and show that M\mathscr{M} is inductive (Set Theory, III, p. 154). Let (uα)(u_\alpha) be a totally ordered subset of M\mathscr{M} and [t0,bα[[t_0, b_\alpha[ the interval where uαu_\alpha is defined: for bα≤bβb_\alpha \leq b_\beta the function uβu_\beta is thus an extension of uαu_\alpha. The union of the intervals [t0,bα[[t_0, b_\alpha[ is an interval [t0,b[[t_0, b[ contained in J, and there exists one and only one function u defined on [t0,b[[t_0, b[ that coincides with uαu_\alpha on [t0,bα[[t_0, b_\alpha[ for each α\alpha; among the bαb_\alpha there is an increasing sequence (bαn)(b_{\alpha_n}) tending to b; since u agrees with uαnu_{\alpha_n} on [t0,bαn[[t_0, b_{\alpha_n}[ the function u admits a derivative satisfying (7) at all the points of the complement of a countable subset of [t0,b[[t_0, b[, and so is the supremum of the set (uα)(u_\alpha) in M\mathscr{M}.

By Zorn's lemma (Set Theory, III, p. 154, th. 2), M\mathscr{M} admits a maximal element u0u_0; we shall show that if [t0,t1[[t_0, t_1[ is the interval where u0u_0 is defined, then either t1t_1 is the right-hand endpoint of J, or else t1−t0≥r/(M+ε)t_1 - t_0 \geq r/(M + \varepsilon). We argue by contradiction, supposing that neither of these conditions holds; first we show that one can extend u0u_0 by continuity at the point t1t_1; in fact, for any s and t in [t0,t1[[t_0, t_1[,

∥u0(s)−u0(t)∥≤(M+ε)∣s−t∣ \|u_0(s) - u_0(t)\| \leq (M + \varepsilon)|s - t|

by the mean value theorem; Cauchy's criterion shows that u0u_0 admits a left limit x1∈Sx_1 \in S at the point t1t_1. Now let c1c_1 be the right limit at t1t_1 of the function f(t,x1)f(t, x_1); one has ∥c1∥≤M\|c_1\| \leq M; the same argument as that at the beginning of the proof shows that one can extend u0u_0 to a half open interval with left-hand endpoint t1t_1 by the function x1+c1(t−t1)x_1 + c_1(t - t_1), so that the extended function belongs to M\mathscr{M}, which is absurd. This proves the proposition.

When f is uniformly continuous on J×SJ \times S one can prove prop. 3 without using Zorn's lemma (IV, p. 199, exerc. 1a)).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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