Bourbaki

Proposition 7

Tag 08D5, permanent. Cite it as [Bourbaki, Tag 08D5].

Functions of a Real Variable, chapter IV, § 2. LINEAR DIFFERENTIAL EQUATIONS

1' The map X↦eXX \mapsto e^X is a continuous map of L(E)\mathscr{L}(E) into the group of automorphisms of E (invertible elements of* L(E)\mathscr{L}(E)).

2 The map t↦eXtt \mapsto e^{Xt} of R\mathbf{R} into L(E)\mathscr{L}(E) is differentiable, and

ddt(eXt)=XeXt=eXtX. \frac{d}{dt} (e^{Xt}) = X e^{Xt} = e^{Xt} X.
(24)

3 For any X∈L(E)X \in \mathscr{L}(E) one has

eX=∑n=0∞Xnn! e^X = \sum_{n=0}^{\infty} \frac{X^n}{n!}
(25)

the right-hand side being absolutely and uniformly convergent on every bounded subset of L(E)\mathscr{L}(E); in particular, eIt=etIe^{It} = e^t I for t∈Rt \in \mathbf{R}.

4) If X and Y commute then Y and eYe^Y commute with eXe^X, and

eX+Y=eXeY. e^{X+Y} = e^X e^Y.
(26)

The relation (24) follows from the expression (23) for C(t,0)C(t, 0) and from the fact that this function is an integral of (20); by recursion on n one deduces from (24) that t↦eXtt \mapsto e^{Xt} is indefinitely differentiable on R\mathbf{R} and that

Dn(eXt)=XneXt. D^n (e^{Xt}) = X^n e^{Xt}.

By Taylor’s formula one thus can write

eX=I+X1!+X22!+⋯+Xnn!+Xn+1∫01(1−t)nn!eXt dt. e^X = I + \frac{X}{1!} + \frac{X^2}{2!} + \cdots + \frac{X^n}{n!} + X^{n+1} \int_0^1 \frac{(1-t)^n}{n!} e^{Xt} \, dt.
(27)

On the other hand, cor. 3 of IV, p. 181 shows that ∥eXt∥≤exp⁡(∥X∥∣t∣)\| e^{Xt} \| \leq \exp (\| X \| |t| ). Thus the remainder rn(X)=Xn+1∫01(1−t)nn!eXt dtr_n(X) = X^{n+1} \int_0^1 \frac{(1-t)^n}{n!} e^{Xt} \, dt in formula (27) satisfies the inequality

∥rn(X)∥≤∥X∥n+1(n+1)!e∥X∥ \| r_n(X) \| \leq \frac{\| X \|^{n+1}}{(n+1)!} e^{\| X \| }

whence one deduces the formula (25), the series on the right-hand side being absolutely and uniformly convergent on every bounded subset of L(E)\mathscr{L}(E). For every pair of elements X, TX,\ T of L(E)\mathscr{L}(E) one thus has

eX+T−eX=∑n=1∞1n!((X+T)n−Xn). e^{X+T} - e^X = \sum_{n=1}^{\infty} \frac{1}{n!} ((X+T)^n - X^n ).

Now, one can write (X+T)n−Xn=∑(Vi)V1V2…Vn(X + T)^n - X^n = \sum_{(V_i)} V_1 V_2 \ldots V_n, where the sum is taken over the 2n−12^n - 1 sequences (Vi)(V_i) of elements of L(E)\mathscr{L}(E) such that Vi=XV_i = X or Vi=TV_i = T for 1≤i≤n1 \leq i \leq n, and at least one of the ViV_i is equal to TT; the inequality

∥(X+T)n−Xn∥≤(∥X∥+∥T∥)n−∥X∥n \|(X + T)^n - X^n\| \leq (\|X\| + \|T\|)^n - \|X\|^n
follows immediately, whence
∥exp⁡(X+T)−exp⁡X∥≤exp⁡(∥X∥+∥T∥)−exp⁡∥X∥ \|\exp(X + T) - \exp X\| \leq \exp \left( \|X\| + \|T\| \right) - \exp \|X\|
which establishes the continuity of the map X↦exp⁡XX \mapsto \exp X.

Finally, if XX and YY commute, then YY commutes with eXte^{Xt} (IV, p. 181, prop. 2), so

ddt(eXteYt)=XeXteYt+eXt(YeYt)=(X+Y)eXteYt. \frac{d}{dt} (e^{Xt} e^{Yt}) = X e^{Xt} e^{Yt} + e^{Xt} (Y e^{Yt}) = (X + Y) e^{Xt} e^{Yt}.
Since, on the other hand, eXteYte^{Xt} e^{Yt} is equal to II for t=0t = 0, one has eXteYt=e(X+Y)te^{Xt} e^{Yt} = e^{(X+Y)t}, whence formula (26). From this latter, one deduces in particular that for arbitrary real ss and tt one has
eX(s+t)=eXseXt e^{X(s+t)} = e^{Xs} e^{Xt}
and also that
e−X=(eX)−1. e^{-X} = (e^X)^{-1}.

On the contrary one notes that (26) need not remain valid if XX and YY are no longer assumed to commute: indeed it would imply that exp⁡X\exp X and exp⁡Y\exp Y always commute, which is not the case, as is shown by simple examples (IV, p. 204, exerc. 3).

Now let us assume that EE is a vector space of finite dimension over the field C\mathbf{C}, and AA an endomorphism of EE (for its vector space structure over C\mathbf{C}) which one can identify with its matrix with respect to a basis of EE; then, for all t∈Rt \in \mathbf{R}, eAte^{At} is an automorphism of EE for the same structure (IV, p. 181, prop. 2). Let rkr_k (1≤k≤q1 \leq k \leq q) be the distinct roots (in C\mathbf{C}) of the characteristic polynomial φ(r)=det⁡(A−rI)\varphi(r) = \det(A - rI) of the endomorphism AA (the "characteristic roots" of AA); if nkn_k is the order of multiplicity of rkr_k then ∑k=1qnk=n\sum_{k=1}^q n_k = n. One knows that (Alg., VII, 31, n° 3) to each root rkr_k there corresponds a subspace EkE_k of EE, of dimension nkn_k, such that EkE_k is stable under AA, and that EE is the direct sum of the EkE_k: EkE_k can be defined as the subspace of vectors x\mathbf{x} such that

(A−rkI)nk.x=0. (A - r_k I)^{n_k} . \mathbf{x} = 0.
Let a\mathbf{a} be any vector in EE; one can write a=∑k=1qak\mathbf{a} = \sum_{k=1}^q \mathbf{a}_k, where ak∈Ek\mathbf{a}_k \in E_k; the integral of the equation (19) of IV, p. 188, taking the value a\mathbf{a} at the point t=0t = 0 is thus given by
u(t)=eAt.a=∑k=1qeAt.ak=∑k=1qerkte(A−rkI)t.ak. \mathbf{u}(t) = e^{At} . \mathbf{a} = \sum_{k=1}^q e^{At} . \mathbf{a}_k = \sum_{k=1}^q e^{r_k t} e^{(A - r_k I)t} . \mathbf{a}_k.

But since ak∈Ek\mathbf{a}_k \in E_k one has

e(A−rkI)t⋅ak=ak+t1!(A−rkI)⋅ak+t22!(A−rkI)2⋅ak+⋯ e^{(A - r_k I)t} \cdot \mathbf{a}_k = \mathbf{a}_k + \frac{t}{1!}(A - r_k I) \cdot \mathbf{a}_k + \frac{t^2}{2!}(A - r_k I)^2 \cdot \mathbf{a}_k + \cdots
+tnk−1(nk−1)!(A−rkI)nk−1⋅ak. + \frac{t^{n_k - 1}}{(n_k - 1)!}(A - r_k I)^{n_k - 1} \cdot \mathbf{a}_k .

Thus every integral of the equation (19) of IV, p. 188, can be written as

u(t)=∑k=1qerktpk(t) \mathbf{u}(t) = \sum_{k=1}^q e^{r_k t} \mathbf{p}_k(t)

where pk(t)\mathbf{p}_k(t) is a polynomial in tt, with coefficients in the vector space EkE_k, and of degree ≤nk−1\leq n_k - 1. In particular, if all the roots of the characteristic equation of AA are simple, the spaces EkE_k (1≤k≤n1 \leq k \leq n) are all of dimension 1 over the field C\mathbf{C}, so there exist nn vectors ckc_k such that the nn functions erktcke^{r_k t} c_k (1≤k≤n1 \leq k \leq n) form a fundamental system of integrals of the equation (19) of IV, p. 188.

The characteristic roots of the endomorphism AA are also called characteristic roots of the linear equation (19) of IV, p. 188. One may observe that one obtains the characteristic equation of AA by writing that the function certc e^{r t} is an integral of (19) for a vector c≠0c \neq 0.

When one has determined the roots rkr_k (1≤k≤q1 \leq k \leq q) explicitly, and thus the order of multiplicity nkn_k of rkr_k, in practice one obtains the integrals of (19) by writing that this equation is satisfied by the expression (32) of IV, p. 191, where pk\mathbf{p}_k is an arbitrary polynomial of degree ≤nk−1\leq n_k - 1, with coefficients in EE; on identifying the coefficients of erkte^{r_k t} (for 1≤k≤q1 \leq k \leq q) in the two sides of the equation so obtained one obtains linear equations for the coefficients of the polynomials pk\mathbf{p}_k: one establishes easily that these equations determine the terms of degree >0> 0 of pk\mathbf{p}_k as functions of the constant term, and that the latter is a solution of the equation (A−rkI)nk⋅x=0(A - r_k I)^{n_k} \cdot \mathbf{x} = 0, which defines the subspace EkE_k (method of "undetermined coefficients").

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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