Bourbaki

Remark

Tag 08FP, permanent. Cite it as [Bourbaki, Tag 08FP].

Functions of a Real Variable, chapter V, § 3. ASYMPTOTIC EXPANSIONS OF FUNCTIONS OF A REAL VARIABLE

Prop. 8 does not apply directly to a function ff of order −1-1 relative to xx. But then one can write f(x)=f1(x)/xf(x) = f_1(x)/x, with f1f_1 of order 0 relative to xx. Suppose, for example, that ∫a+∞f(t) dt\int_a^{+\infty} f(t)\,dt is infinite; then

F(x)=∫axf(t) dt=∫ax1tf1(t) dt=∫log⁡alog⁡xf1(eu) du. F(x) = \int_a^x f(t)\,dt = \int_a^x \frac{1}{t} f_1(t)\,dt = \int_{\log a}^{\log x} f_1(e^u)\,du.

If the function f1(et)f_1(e^t) satisfies the hypotheses of prop. 8 and has an order ≠−1\neq -1 relative to yy (that is, if f1(x)f_1(x) has an order ≠−1\neq -1 relative to log⁡x\log x) the formulae (1) and (2) again allow us to obtain a principal part for F(x)F(x). For example, let f(x)=exp⁡(log⁡x)xlog⁡xf(x) = \frac{\exp(\sqrt{\log x})}{x \log x}; since exp⁡(log⁡x)\exp(\sqrt{\log x}) is of order 0 relative to xx, ff is of order −1-1; here one has f1(et)=et/yf_1(e^t) = e^{\sqrt{t}}/y, and this function is of order +∞+\infty relative to yy; prop. 8 applies and gives ∫axeu/u du∼2ey/y\int_a^x e^{\sqrt{u}}/u\,du \sim 2e^{\sqrt{y}}/\sqrt{y}: on reverting to the variable xx we have ∫axexp⁡(log⁡t)tlog⁡t dt∼2exp⁡(log⁡x)log⁡x\int_a^x \frac{\exp(\sqrt{\log t})}{t \log t}\,dt \sim \frac{2\exp(\sqrt{\log x})}{\sqrt{\log x}}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.