Bourbaki

Proposition 8

Tag 08FM, permanent. Cite it as [Bourbaki, Tag 08FM].

Functions of a Real Variable, chapter V, § 3. ASYMPTOTIC EXPANSIONS OF FUNCTIONS OF A REAL VARIABLE

Put F(x)=∫x+∞f(t) dtF(x) = \int_x^{+\infty} f(t)\,dt if ∫a+∞f(t) dt\int_a^{+\infty} f(t)\,dt converges, and F(x)=∫axf(t) dtF(x) = \int_a^x f(t)\,dt if ∫a+∞f(t) dt\int_a^{+\infty} f(t)\,dt is infinite. Suppose that log⁡∣f∣\log|f| and log⁡x\log x are comparable of order 1.

1 If ff is of finite order μ≠−1\mu \neq -1 with respect to xx one has

F(x)∼1∣μ+1∣xf(x). F(x) \sim \frac{1}{|\mu+1|} x f(x).
(1)

2 If ff is of infinite order relative to xx and if f/f′f/f' and xx are comparable of order 1, then one has

F(x)∼(f(x))2∣f′(x)∣. F(x) \sim \frac{(f(x))^2}{|f'(x)|}.
(2)

One should note that the hypothesis implies that f(x)f(x) has a determinate order relative to xx (V, p. 219).

1 If ff is of order μ≠0\mu \neq 0 relative to xx one has log⁡∣f∣∼μlog⁡x\log|f| \sim \mu \log x, so, since log⁡∣f∣\log|f| and log⁡x\log x are comparable of order 1, by prop. 7 of V, p. 232 one has f′/f∼f'/f \sim μ/x, whence xf′∼μfx f' \sim \mu f. If μ>−1\mu > -1 one has f(x)≫xμ−εf(x) \gg x^{\mu-\varepsilon} for every ε>0\varepsilon > 0, and hence (V, p. 229, prop. 2) the integral ∫a+∞f(t) dt\int_a^{+\infty} f(t)\,dt is infinite. One can write F(x)=∫axf(t) dt=xf(x)−af(a)−∫axtf′(t) dtF(x) = \int_a^x f(t)\,dt = x f(x) - af(a) - \int_a^x t f'(t)\,dt, whence again

∫ax(f(t)+tf′(t)) dt=xf(x)−af(a); \int_a^x (f(t) + t f'(t))\,dt = x f(x) - af(a);
since μ≠−1\mu \neq -1 we have f(x)+xf′(x)∼(μ+1)f(x)f(x) + x f'(x) \sim (\mu + 1) f(x), so (V, p. 230, prop. 6)
∫ax(f(t)+tf′(t)) dt∼(μ+1)F(x), \int_a^x (f(t) + t f'(t))\,dt \sim (\mu + 1) F(x),
which proves (1) in this case. If μ=0\mu = 0 one has likewise that xf′(x)≪f(x)x f'(x) \ll f(x), which again gives f(x)+xf′(x)∼f(x)f(x) + x f'(x) \sim f(x). One argues similarly when μ<−1\mu < -1, in the case where ∫a+∞f(t) dt\int_a^{+\infty} f(t)\,dt converges.

2) If ff is of order +∞+\infty relative to xx one has log⁡∣f∣≫log⁡x\log |f| \gg \log x, so (V, p. 232, prop. 7) f′/f≫1/xf'/f \gg 1/x, or again, putting g(x)=f(x)/f′(x)g(x) = f(x)/f'(x), g(x)≪xg(x) \ll x; further, since f(x)≫xαf(x) \gg x^\alpha for every α>0\alpha > 0 the integral ∫a+∞f(t) dt\int_a^{+\infty} f(t)\,dt is infinite. One can write

F(x)=∫axf(t) dt=∫axg(t)f′(t) dt=g(x)f(x)−g(a)f(a)−∫axf(t)g′(t) dt; F(x) = \int_a^x f(t)\,dt = \int_a^x g(t) f'(t)\,dt = g(x) f(x) - g(a) f(a) - \int_a^x f(t) g'(t)\,dt;
since gg and xx are comparable of order 1, from the relation g(x)≪xg(x) \ll x one can deduce (V, p. 232, prop. 7) that g′(x)≪1g'(x) \ll 1, hence that fg′≪ff g' \ll f, and consequently (V, p. 230, prop.6)
∫axf(t)g′(t) dt≪F(x), \int_a^x f(t) g'(t)\,dt \ll F(x),
which establishes the relation (2). The proof is similar when ff is of order −∞-\infty relative to xx, in the case where ∫a+∞f(t) dt\int_a^{+\infty} f(t)\,dt converges.

Let E\mathscr{E} be a comparison scale (for real xx tending to +∞+\infty) formed of nonzero real functions that are of constant sign on a neighbourhood of +∞+\infty, such that x∈Ex \in \mathscr{E} and such that the product and quotient of two functions in E\mathscr{E} again belongs to E\mathscr{E} (V, p. 221 and p. 224). If a regulated function ff with constant sign on a neighbourhood of +∞+\infty has a principal part cgc g relative to E\mathscr{E}, then ∫x+∞f(t) dt\int_x^{+\infty} f(t)\,dt (resp. ∫axf(t) dt\int_a^x f(t)\,dt according to the case) will be equivalent to c∫x+∞g(t) dtc \int_x^{+\infty} g(t)\,dt (resp. c∫axg(t) dtc \int_a^x g(t)\,dt); if the function gg satisfies the hypotheses of prop. 8 of V, p. 233, and if (when the formula (2) of V, p. 233, applies) one knows a principal part of g′g' relative to E\mathscr{E}, one will thus have a principal part of ∫x+∞f(t) dt\int_x^{+\infty} f(t)\,dt (resp. ∫axf(t) dt\int_a^x f(t)\,dt) relative to E\mathscr{E}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed volume. Not translated.