Library / Functions of a Real Variable / Chapter V / § 4
Example
Tag 08GA, permanent. Cite it as [Bourbaki, Tag 08GA].
Functions of a Real Variable, chapter V, § 4. APPLICATION TO SERIES WITH POSITIVE TERMS
Consider the hypergeometric series , with general term
u n = α ( α + 1 ) … ( α + n − 1 ) β ( β + 1 ) … ( β + n − 1 ) 1.2 … n . γ ( γ + 1 ) … ( γ + n − 1 )
u_n = \frac{\alpha(\alpha+1)\ldots(\alpha+n-1)\,\beta(\beta+1)\ldots(\beta+n-1)}{1.2\ldots n.\gamma(\gamma+1)\ldots(\gamma+n-1)}
u n = 1.2 … n . γ ( γ + 1 ) … ( γ + n − 1 ) α ( α + 1 ) … ( α + n − 1 ) β ( β + 1 ) … ( β + n − 1 )
where α , β , γ \alpha, \beta, \gamma α , β , γ are arbitrary real numbers, not integers ≤ 0 \leq 0 ≤ 0 : it is clear that u n u_n u n is > 0 > 0 > 0 from a certain stage, or < 0 < 0 < 0 from a certain stage on. One has
u n + 1 u n = ( α + n ) ( β + n ) ( n + 1 ) ( γ + n ) = ( 1 + α + β n + α β n 2 ) ( 1 + γ + 1 n + γ n 2 ) − 1 = 1 + α + β − γ − 1 n + α β − ( α + β ) ( γ + 1 ) + γ 2 + γ + 1 n 2 + o ( 1 n 2 ) .
\begin{align*}
\frac{u_{n+1}}{u_n} &= \frac{(\alpha+n)(\beta+n)}{(n+1)(\gamma+n)} \\
&= \left(1 + \frac{\alpha+\beta}{n} + \frac{\alpha\beta}{n^2}\right) \left(1 + \frac{\gamma+1}{n} + \frac{\gamma}{n^2}\right)^{-1} \\
&= 1 + \frac{\alpha+\beta-\gamma-1}{n} \\
&\quad + \frac{\alpha\beta-(\alpha+\beta)(\gamma+1)+\gamma^2+\gamma+1}{n^2} + o\left(\frac{1}{n^2}\right).
\end{align*}
u n u n + 1 = ( n + 1 ) ( γ + n ) ( α + n ) ( β + n ) = ( 1 + n α + β + n 2 α β ) ( 1 + n γ + 1 + n 2 γ ) − 1 = 1 + n α + β − γ − 1 + n 2 α β − ( α + β ) ( γ + 1 ) + γ 2 + γ + 1 + o ( n 2 1 ) .
Raabe's test shows that the series converges for α + β < γ \alpha + \beta < \gamma α + β < γ , and has infinite sum for α + β > γ \alpha + \beta > \gamma α + β > γ ; when α + β = γ \alpha + \beta = \gamma α + β = γ the series also has an infinite sum, as is shown by prop. 8.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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Transcribed from the printed volume. Not translated.