Bourbaki

Corollary 2

Tag 08N3, permanent. Cite it as [Bourbaki, Tag 08N3].

Integration, chapter III, § 2. Support of a measure

— Let μ\mu be a positive measure on XX; if f∈K(X;C)f \in \mathscr{K}(X; \mathbf{C}) is such that f(x)≥0f(x) \geq 0 on Supp⁡(μ)\operatorname{Supp}(\mu), then μ(f)≥0\mu(f) \geq 0.

For, f=∣f∣f = |f| on Supp⁡(μ)\operatorname{Supp}(\mu), therefore μ(f)=μ(∣f∣)≥0\mu(f) = \mu(|f|) \geq 0 by Corollary 1.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.