Bourbaki

Proposition 4

Tag 08NU, permanent. Cite it as [Bourbaki, Tag 08NU].

Integration, chapter III, § 3. Integrals of continuous vector-valued functions

— Let μ\mu be a positive measure on XX, SS its support, and ff a function in K~(X;E)\widetilde{\mathscr{K}}(X;E). Suppose EE is Hausdorff, and equip the space E′∗{E'}^* with the weak topology σ(E′∗,E′)\sigma({E'}^*, E').

(i) The integral ∫f dμ\int f\, d\mu belongs to the closure C in E'** of the convex cone generated by f(S).

(ii) If μ\mu is bounded, then the integral ∫f dμ\int f\, d\mu belongs to the set ∥μ∥⋅D\| \mu \| \cdot D, where D is the closed convex envelope of f(S) in E'**.

If E is complex, we equip E with its underlying real vector space structure, which, as we have seen, does not modify the formula (1).

(i) We know that C is the intersection of the closed half-spaces in E'** that contain f(S) and are determined by closed hyperplanes passing through 0; it therefore suffices to prove that, for z′∈E′z' \in E', the relation ⟨f(x),z′⟩≥0\langle f(x), z' \rangle \geq 0 for all x∈Sx \in S implies

⟨∫f dμ,z′⟩≥0; \left\langle \int f\, d\mu, z' \right\rangle \geq 0;

but since

⟨∫f dμ,z′⟩=∫⟨f,z′⟩ dμ, \left\langle \int f\, d\mu, z' \right\rangle = \int \langle f, z' \rangle\, d\mu,

this follows from §2, No. 3, Cor. 2 of Prop. 8.

(ii) We know that D is the intersection of the closed half-spaces in E'** that contain f(S); it therefore suffices to show that, for z′∈E′z' \in E', the relation ⟨f(x),z′⟩≤a\langle f(x), z' \rangle \leq a for all x∈Sx \in S implies

⟨∫f dμ,z′⟩≤a∥μ∥; \left\langle \int f\, d\mu, z' \right\rangle \leq a \| \mu \|;

but this follows from §2, No. 3, Cor. 3 of Prop. 8.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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