Bourbaki

Proposition 5

Tag 08NW, permanent. Cite it as [Bourbaki, Tag 08NW].

Integration, III, p. 36, § 3. Integrals of continuous vector-valued functions

Suppose that the space X is compact, and let f be a continuous mapping of X into a Hausdorff locally convex space E. The closed convex envelope of f(X) in E'** (for σ(E′,E′)\sigma(E', E')) is equal to the set of vectors ∫f dμ\int f\, d\mu for all of the positive measures μ\mu on X of total mass 1.

Let C be the closed convex envelope of f(X) in E'; since f(X) is compact and E' is complete, C is compact. We already know (Prop. 4) that ∫fdμ∈C\int f d\mu \in C for every measure μ\mu belonging to the convex set HH of positive measures on XX of total mass equal to 1. On the other hand, HH is convex and compact for the vague topology (§ 1, No. 9, Cor. 3 of Prop. 15) and is the closure (for this topology) of the convex set H0H_0 of positive measures of mass 1 and finite support (§ 2, No. 4, Cor. 3 of Th. 1). Now, the image of H0H_0 under the mapping μ↦∫fdμ\mu \mapsto \int f d\mu is the convex envelope C0C_0 of f(X)f(X) in E′∗{E'}^*. On the other hand, this mapping is continuous for the vague topology on M(X;C)\mathscr{M}(X; C) and the topology σ(E′∗,E′)\sigma({E'}^*, E') on E′∗{E'}^* since ⟨∫fdμ,z′⟩=∫⟨f,z′⟩dμ\langle \int f d\mu, z' \rangle = \int \langle f, z' \rangle d\mu by definition; thus the image of H=H0‾H = \overline{H_0} is a compact convex set containing C0C_0 and contained in CC; since C=C0‾C = \overline{C_0}, this image is equal to CC.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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