Bourbaki

Proposition 5

Tag 08OL, permanent. Cite it as [Bourbaki, Tag 08OL].

Integration, chapter III, § 4. Products of measures

For every measure λ0∈M(X;C)\lambda_0 \in \mathscr{M}(X; \mathbf{C}), the mapping μ↦λ0⊗μ\mu \mapsto \lambda_0 \otimes \mu of M(Y;C)\mathscr{M}(Y; \mathbf{C}) into M(X×Y;C)\mathscr{M}(X \times Y; \mathbf{C}) is vaguely continuous.

For every function f∈K(X×Y;C)f \in \mathscr{K}(X \times Y; \mathbf{C}), we know that the function h(y)=∫f(x,y)dλ0(x)h(y) = \int f(x, y) d\lambda_0(x) belongs to K(Y;C)\mathscr{K}(Y; \mathbf{C}) (No. 1, Lemma 2), and ⟨f,λ0⊗μ⟩=⟨h,μ⟩\langle f , \lambda_0 \otimes \mu \rangle = \langle h , \mu \rangle, whence the proposition.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.