— Let (Ik)1≤k≤r be a partition of the interval [1,n] of N; then
k=1⨂r(i∈Ik⨂μi)=i=1⨂nμi
For, these two measures coincide, by (12), for every function in ⨂i=1nK(Xi;C).
The integral of a function f∈K(X;C) with respect to the product measure is denoted
∫fdμ1dμ2…dμn, or
∭…∫fdμ1dμ2…dμn or
∫f(μ1⊗⋯⊗μn) or also
∭…∫f(x1,x2,…,xn)dμ1(x1)dμ2(x2)…dμn(xn) or
∭…∫f(x1,x2,…,xn)μ1(x1)μ2(x2)…μn(xn) with
n signs
∫; it is said to be a
multiple integral of order n, or an
n-tuple integral. By virtue of the associativity of the product of measures and the theorem on inverting the order of integration (No. 1, Th. 2), we have, for every permutation
σ of
[1,n],
∭…∫fdμ1dμ2…dμn=∫dμσ(1)∫dμσ(2)…∫fdμσ(n). (14)
The integral notation and formula (14) may be extended in an obvious way to functions f∈K(X;E) with values in a Hausdorff locally convex space E, such that f(X) is contained in a complete convex subset of E. We leave to the reader the task of generalizing to the product of any finite number of measures the results of Nos. 2 and 3 concerning the product of two measures.
In particular, one calls Lebesgue measure on Rn the product of n measures identical to the Lebesgue measure on R; the integral of a function f∈K(Rn;E), satisfying the preceding condition, is denoted
∭…∫f(x1,x2,…,xn)dx1dx2…dxn and is equal to
∫−∞+∞dx1∫−∞+∞dx2…∫−∞+∞f(x1,x2,…,xn)dxn. Lebesgue measure on
Rn is
invariant under every translation.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.