Bourbaki

Theorem 2

Tag 08P8, permanent. Cite it as [Bourbaki, Tag 08P8].

Integration, chapter IV, § 1. Upper integral of a positive function

If f1f_1 and f2f_2 are two functions in I+\mathscr{I}_+ then

μ∗(f1+f2)=μ∗(f1)+μ∗(f2). \mu^*(f_1 + f_2) = \mu^*(f_1) + \mu^*(f_2).

As φ1\varphi_1 (resp. φ2\varphi_2) runs over the set of functions in K+\mathscr{K}_+ such that φ1≤f1\varphi_1 \leq f_1 (resp. φ2≤f2\varphi_2 \leq f_2), the functions φ1+φ2\varphi_1 + \varphi_2 form a directed set (for ≤\leq) whose upper envelope is f1+f2f_1 + f_2. Therefore, by Th. 1,

μ∗(f1+f2)=sup⁡μ(φ1+φ2)=sup⁡(μ(φ1)+μ(φ2)), \mu^*(f_1 + f_2) = \sup \mu(\varphi_1 + \varphi_2) = \sup (\mu(\varphi_1) + \mu(\varphi_2)),

where (φ1,φ2)(\varphi_1, \varphi_2) runs over the set of pairs of functions in K+\mathscr{K}_+ such that φ1≤f1\varphi_1 \leq f_1 and φ2≤f2\varphi_2 \leq f_2; since

sup⁡(μ(φ1)+μ(φ2))=sup⁡μ(φ1)+sup⁡μ(φ2) \sup (\mu(\varphi_1) + \mu(\varphi_2)) = \sup \mu(\varphi_1) + \sup \mu(\varphi_2)

(GT, IV, §5, No. 7, Cor. 2 of Prop. 12), the theorem is proved.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.