Bourbaki

Example

Tag 08Z2, permanent. Cite it as [Bourbaki, Tag 08Z2].

Integration, chapter IV, § 7. Barycenters

— Take X to be the unit ball ∥x∥≤1\|x\| \leq 1 in R3\mathbf{R}^3, and let H\mathscr{H} be a vector space of continuous functions on X, containing the restrictions to X of the affine linear functions on R3\mathbf{R}^3 and satisfying the maximum principle, that is, for every non-constant function h∈Hh \in \mathscr{H}, the set of points of X where h attains its supremum is contained in the sphere S2S_2. It then follows easily from Props. 5 and 7 that Ch⁡H(X)=SˇH(X)=S2\operatorname{Ch}_{\mathscr{H}}(X) = \check{S}_{\mathscr{H}}(X) = S_2. An important example of a vector space H\mathscr{H} satisfying the preceding conditions is the set of functions continuous on X and harmonic in the open ball ∥x∥<1\|x\| < 1. For these functions, one proves that the positive measure μ\mu of mass 1 such that Supp⁡(μ)⊂S2\operatorname{Supp}(\mu) \subset S_2 and h(x)=∫h dμh(x) = \int h \, d\mu for all h∈Hh \in \mathscr{H} is given, if ∥x∥<1\|x\| < 1, by Poisson’s formula

dμ(z)=1−∥z∥2∥z−x∥3dσ(z), d\mu(z) = \frac{1 - \|z\|^2}{\|z - x\|^3} d\sigma(z),

where σ\sigma is the measure on S2S_2 invariant under the orthogonal group and such that σ(S2)=1\sigma(S_2) = 1 (Ch. VII, §3, Exer. 8).*

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.