Bourbaki

Remark

Tag 0971, permanent. Cite it as [Bourbaki, Tag 0971].

Integration, chapter V, § 8. Products of measures

Lemmas 1,2,3 can be proved very simply without making use of the results of §§4 and 6, by a direct argument. For example, the relation (2) is obvious by definition if f∈K(T×T′)f \in \mathscr{K}(T \times T'). If ff is lower semi-continuous on X=T×T′X = T \times T', it suffices to observe that t′↦ft(t′)t' \mapsto f_t(t') is the upper envelope of the functions t′↦gt(t′)=g(t,t′)t' \mapsto g_t(t') = g(t, t'), where gg runs over the set of functions in K(X)\mathscr{K}(X) such that 0≤g≤f0 \leq g \leq f. Finally, for arbitrary ff, one notes that if h≥fh \geq f is lower semi-continuous on XX, then t′↦h(t,t′)t' \mapsto h(t, t') is lower semi-continuous on T′T'; and conversely, if t′↦u(t′)t' \mapsto u(t') is lower semi-continuous on T′T' and is such that u(t′)≥f(t,t′)u(t') \geq f(t, t') for all t′∈T′t' \in T', then the function hh such that h(t,t′)=u(t′)h(t, t') = u(t'), h(t1,t′)=+∞h(t_1, t') = +\infty for t1≠t′t_1 \neq t', is lower semi-continuous on XX and satisfies h≥fh \geq f. Once Lemma 1 is proved, one deduces from it that the set (T−{t})×T′(T - \{t\}) \times T' is λt′\lambda'_t-negligible, and it is then every easy to prove Lemmas 2 and 3.

The relation (3) permits denoting its two members by ∫f(t,t′) dμ′(t′)\int f(t, t') \, d\mu'(t') without risk of confusion. The analogous results obviously hold for the measures λt′=μ⊗εt′\lambda_{t'} = \mu \otimes \varepsilon_{t'}.

Instead of the notations

∫∗f(t,t′) dν(t,t′),∫∙f(t,t′) dν(t,t′),∫f(t,t′) dν(t,t′), \int^* f(t, t') \, d\nu(t, t'), \quad \int^\bullet f(t, t') \, d\nu(t, t'), \quad \int f(t, t') \, d\nu(t, t'),

we shall employ the notations

∬∗f(t,t′) dμ(t) dμ′(t′),∬∙f(t,t′) dμ(t) dμ′(t′),∬f(t,t′) dμ(t) dμ′(t′), \iint^* f(t, t') \, d\mu(t) \, d\mu'(t'), \quad \iint^\bullet f(t, t') \, d\mu(t) \, d\mu'(t'), \quad \iint f(t, t') \, d\mu(t) \, d\mu'(t'),

consistent with the notations adopted in Ch. III, §4, No. 1.

The interpretation of the measure ν\nu as an integral ∫λt′ dμ(t)\int \lambda'_t \, d\mu(t) will allow us to translate the results of §3 into the language of product measures. On the other hand, the measure λt′\lambda'_t is carried by {t}×T′=pr‾1−1(t)\{t\} \times T' = \overline{\mathrm{pr}}_1^{-1}(t), so that this integral defines a decomposition of ν\nu into slices, relative to the projection pr1\mathrm{pr}_1 of T×T′T \times T' onto TT (§6, No. 6). Before giving a list of the results so obtained, here is a useful property:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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