Bourbaki

Corollary 1

Tag 09G4, permanent. Cite it as [Bourbaki, Tag 09G4].

Integration, chapter VII, § 2. Quotient of a space by a group; homogeneous spaces

— a) Let f be a function on X/H', with values in a Banach space or in R‾\overline{\mathbf{R}}, integrable for μ/β′\mu/\beta'. There exists a (μ/β)(\mu/\beta)-negligible subset N of X/H having the following property: if x∈Xx \in X is such that π(x)∉N\pi(x) \notin N, then the function f∘ωxf \circ \omega_x on H/H', that is, the function ξ˙↦f(π′(xξ))\dot{\xi} \mapsto f(\pi'(x\xi)), is integrable for β/β′\beta/\beta'. The integral ∫H/H′f(π′(xξ))d(β/β′)(ξ˙)\int_{H/H'} f(\pi'(x\xi)) d(\beta/\beta')(\dot{\xi}) depends only on x˙=π(x)\dot{x} = \pi(x), and is a (μ/β)(\mu/\beta)-integrable function of x˙\dot{x}; and

∫X/H′fd(μ/β′)=∫X/Hd(μ/β)(x˙)∫H/H′f(π′(xξ))d(β/β′)(ξ˙). \int_{X/H'} f d(\mu/\beta') = \int_{X/H} d(\mu/\beta)(\dot{x}) \int_{H/H'} f(\pi'(x\xi)) d(\beta/\beta')(\dot{\xi}).

b) Let ff be a function ≥0\geq 0 on X/H′X/H', measurable for μ/β′\mu/\beta' and zero outside a countable union of (μ/β′)(\mu/\beta')-integrable sets. Then

π(x)↦∫H/H′∗f(π′(xξ))d(β/β′)(ξ˙) \pi(x) \mapsto \int_{H/H'}^* f(\pi'(x\xi)) d(\beta/\beta')(\dot{\xi})

is (μ/β)(\mu/\beta)-measurable, and

∫X/H′∗fd(μ/β′)=∫X/H∗d(μ/β)(x˙)∫H/H′∗f(π′(xξ))d(β/β′)(ξ˙). \int_{X/H'}^* f d(\mu/\beta') = \int_{X/H}^* d(\mu/\beta)(\dot{x}) \int_{H/H'}^* f(\pi'(x\xi)) d(\beta/\beta')(\dot{\xi}).

c) Let ff be a function on X/H′X/H' with values in a Banach space or in R‾\overline{\mathbf{R}}, measurable for μ/β′\mu/\beta' and zero outside a countable union of (μ/β′)(\mu/\beta')-integrable sets. Then, for ff to be (μ/β′)(\mu/\beta')-integrable, it is sufficient that

∫X/H∗d(μ/β)(x˙)∫H/H′∗∣f(π′(xξ))∣d(β/β′)(ξ˙)<+∞. \int_{X/H}^* d(\mu/\beta)(\dot{x}) \int_{H/H'}^* |f(\pi'(x\xi))| d(\beta/\beta')(\dot{\xi}) < +\infty.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Nothing.

Transcribed from the printed volume. Not translated.