Bourbaki

Proposition 5

Tag 09H3, permanent. Cite it as [Bourbaki, Tag 09H3].

Integration, VII, p. 59, § 3. Applications and examples

Let G be a connected topological group admitting a discrete normal subgroup D such that K = G/D is compact, and such that the commutator subgroup of K is dense in K. Then D is finite and G is compact.

The group G is locally isomorphic to K (GT, III, §2, No. 6, Prop. 19), hence is locally compact; since it is connected, it is generated by a compact neighborhood of e. By Lemmas 3 and 4, D is a finitely generated abelian group, hence is isomorphic to a group Zr×D1\mathbf{Z}^r \times D_1 with D_1 finite (A, VII, §4, No. 7, Th. 3). Suppose that r > 0. Then there exists a representation f of D onto Z\mathbf{Z}. By Prop. 4, f may be extended to a continuous representation g of G in R. By passage to quotients, g defines a continuous representation g′g' of KK in R/Z\mathbf{R}/\mathbf{Z}; since R/Z\mathbf{R}/\mathbf{Z} is abelian, the kernel of g′g' contains the commutator subgroup of KK, therefore g′g' is trivial; in other words, g(G)⊂Zg(G) \subset \mathbf{Z}. Since GG is connected, it follows that g(G)={0}g(G) = \{0\}, which is absurd since f(D)=Zf(D) = \mathbf{Z}. Thus r=0r = 0 and DD is finite. Consequently GG is compact (GT, III, §4, No. 1, Cor. 2 of Prop. 2).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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