Bourbaki

Lemma 1

Tag 09HX, permanent. Cite it as [Bourbaki, Tag 09HX].

Integration, chapter VII, Appendix 1.

*Let X be a locally compact space, R an open equivalence relation in X, such that the quotient space X/R is paracompact; let π be the canonical mapping of X onto X/R. There exists a continuous real-valued function F ≥ 0 on X such that:

a) F is not identically zero on any equivalence class with respect to R;

b) for every compact subset K of X/R, the intersection of π‾(K)\overline{\pi}(K) with Supp F is compact.

To each point u∈X/Ru \in X/R let us associate a function fu∈K+(X)f_u \in \mathscr{K}_+(X) such that fuf_u is not identically zero on π‾(u)\overline{\pi}(u); let Ωu\Omega_u be the open set of points where fu>0f_u > 0; thus u∈π(Ωu)u \in \pi(\Omega_u). Since π\pi is an open mapping, the π(Ωu)\pi(\Omega_u) form an open covering of X/R. There exists a locally finite open covering (Uι)ι∈I(U_\iota)_{\iota \in I}, finer than the covering by the π(Ωu)\pi(\Omega_u), then (GT, IX, §4, No. 3, Prop. 3) a partition of unity (gι)ι∈I(g_\iota)_{\iota \in I} on X/R subordinate to the covering (Uι)(U_\iota). For every ι∈I\iota \in I, choose a uιu_\iota such that Uι⊂π(Ωuι)U_\iota \subset \pi(\Omega_{u_\iota}). The function Fι=(gι∘π)⋅fuιF_\iota = (g_\iota \circ \pi) \cdot f_{u_\iota} belongs to K(X)\mathscr{K}(X) and has support contained in π‾(Uι)\overline{\pi}(U_\iota). The supports of the FιF_\iota therefore form a locally finite family, so that one can define a continuous function F≥0F \geq 0 on X by setting F=∑ι∈IFιF = \sum_{\iota \in I} F_\iota.

For every u∈X/Ru \in X/R, there exists an ι\iota such that gι(u)>0g_\iota(u) > 0 and therefore u∈Uιu \in U_\iota; next, there exists an x∈Ωuιx \in \Omega_{u_\iota} such that π(x)=u\pi(x) = u; then fuι(x)>0f_{u_\iota}(x) > 0 and gι(π(x))>0g_\iota(\pi(x)) > 0, therefore Fι(x)>0F_\iota(x) > 0 and a fortiori F(x)>0F(x) > 0; this proves that F has the property a). Finally, let K be a compact subset of X/R. There exists a finite subset J of I such that, for ι∈I−J\iota \in I - J, one

Same as TG, IX, §4, n° 4, prop. 5 (absent from GT).

has Uℓ∩K=∅U_\ell \cap K = \varnothing, therefore π‾−1(K)∩Supp Fℓ=∅\overline{\pi}^{-1}(K) \cap \mathrm{Supp}\ F_\ell = \varnothing. Then the set

π‾−1(K)∩Supp F=π‾−1(K)∩(⋃ℓ∈ISupp Fℓ)=π‾−1(K)∩(⋃ℓ∈JSupp Fℓ) \overline{\pi}^{-1}(K) \cap \mathrm{Supp}\ F = \overline{\pi}^{-1}(K) \cap \left( \bigcup_{\ell \in I} \mathrm{Supp}\ F_\ell \right) = \overline{\pi}^{-1}(K) \cap \left( \bigcup_{\ell \in J} \mathrm{Supp}\ F_\ell \right)
is compact.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.