Bourbaki

Proposition 7

Tag 09R9, permanent. Cite it as [Bourbaki, Tag 09R9].

Integration, chapter IX, § 5. Measures on completely regular spaces

— Let T be a completely regular space. Let μ\mu be a bounded positive measure on T, and let f be a bounded positive function on T, such that the set of points of T where f is not continuous is locally μ\mu-negligible. Then the mapping λ↦λ∗(f)\lambda \mapsto \lambda^*(f) of M+b(T)\mathscr{M}_+^b(T) into R\mathbf{R} is continuous at the point μ\mu.

For every t∈Tt \in T, set f′(t)=lim inf⁡s→tf(s)f'(t) = \liminf_{s \to t} f(s), f′′(t)=lim sup⁡s→tf(s)f''(t) = \limsup_{s \to t} f(s). Obviously f′⩽f⩽f′′f' \leqslant f \leqslant f'', with equality at every point of T where f is continuous (hence μ\mu-almost everywhere). On the other hand, f′f' is lower semi-continuous, f′′f'' is upper semi-continuous and bounded (GT, IV, §6, No. 2, Prop. 4). We therefore have the following relations by Prop. 6,

μ∗(f′)⩽lim inf⁡λ→μλ∗(f′)⩽lim inf⁡λ→μλ∗(f)⩽μ∗(f)⩽lim sup⁡λ→μλ∗(f) \mu^*(f') \leqslant \liminf_{\lambda \to \mu} \lambda^*(f') \leqslant \liminf_{\lambda \to \mu} \lambda^*(f) \leqslant \mu^*(f) \leqslant \limsup_{\lambda \to \mu} \lambda^*(f)
⩽lim sup⁡λ→μλ∗(f′′)⩽μ∗(f′′). \leqslant \limsup_{\lambda \to \mu} \lambda^*(f'') \leqslant \mu^*(f'').

One concludes by observing that μ∗(f′)=μ∗(f′′)\mu^*(f') = \mu^*(f''), because f′f' and f′′f'' are equal locally μ\mu-almost everywhere.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.