Bourbaki

Proposition 11

Tag 0A9N, permanent. Cite it as [Bourbaki, Tag 0A9N].

Lie Groups and Lie Algebras, chapter III, § 3. Passage from a Lie group to its Lie algebra

Let G be a Lie group. (i) The cogebra T(∞)(G)\mathscr{T}^{(\infty)}(G), with convolution, is a bigebra (Algebra, Chapter III, § 11, no. 4). (ii) Let c be the coproduct on T(∞)(G)\mathscr{T}^{(\infty)}(G). Let t∈T(∞)(G)t \in \mathscr{T}^{(\infty)}(G) and write

c(t)=∑i=1nti⊗ti′. c(t) = \sum_{i=1}^n t_i \otimes t_i'.
Then c(t∨)=∑i=1nti∨⊗ti′∨c(t^\vee) = \sum_{i=1}^n t_i^\vee \otimes t_{i'}^\vee.

We prove (i). In the definition of bigebra referred to, condition (1) follows from Propositions 2 and 3 and condition (2) follows from Differentiable and Analytic Manifolds, R, 13.5.1. Let d be the mapping g↦(g,g)g \mapsto (g, g) of G into G×GG \times G. Then c=d∗c = d_* and hence c is an algebra morphism (Propositions 6 and 9), which is condition (3). Let t∈Tg(∞)(G)t \in T_g^{(\infty)}(G), t′∈Tg′(∞)(G)t' \in T_{g'}^{(\infty)}(G) have no constant term and λ,λ′\lambda, \lambda' be elements of K; then εg⊗t′,t⊗εg′,t⊗t′\varepsilon_g \otimes t', t \otimes \varepsilon_{g'}, t \otimes t' are without constant term (Differentiable and Analytic Manifolds, R, 13.4.1) and hence the constant term of (λεg+t)∗(λ′εg′+t′)(\lambda \varepsilon_g + t) * (\lambda' \varepsilon_{g'} + t') is λλ′\lambda \lambda'; hence condition (4) holds.

We prove (ii). By Propositions 8 and 9,

c(t∨)=d∗(t∨)=(d∗(t))∨=(∑i=1nti⊗ti′)∨=∑i=1nti′∨⊗ti′∨. c(t^\vee) = d_*(t^\vee) = (d_*(t))^\vee = \left( \sum_{i=1}^n t_i \otimes t_i' \right)^\vee = \sum_{i=1}^n t_{i'}^\vee \otimes t_{i'}^\vee.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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