Bourbaki

Proposition 12

Tag 0A9O, permanent. Cite it as [Bourbaki, Tag 0A9O].

Lie Groups and Lie Algebras, chapter III, § 3. Passage from a Lie group to its Lie algebra

Let G, H be two Lie groups and ϕ\phi a morphism of G into H. Then ϕ∗\phi_* is a bigebra morphism of T(∞)(G)\mathscr{T}^{(\infty)}(G) into T(∞)(H)\mathscr{T}^{(\infty)}(H).

This follows from Proposition 6 and Differentiable and Analytic Manifolds, R, 13.5.1.

Let G be a Lie group. The restrictions of the convolution and the coproduct to U(G) define a bigebra structure on U(G). We have U(G)^{\vee} = U(G). If ϕ:G→H\phi : G \to H is a Lie group morphism, we denote by U(ϕ\phi) the mapping t↦ϕ∗(t)t \mapsto \phi_*(t) of U(G) into U(H); this is a bigebra morphism. If ψ:H→L\psi : H \to L is another Lie group morphism, then U(ψ∘ϕ\psi \circ \phi) = U(ψ\psi) \circ U(ϕ\phi). If ϕ\phi is an immersion (resp. a submersion), U(ϕ\phi) is injective (resp. surjective) by Differentiable and Analytic Manifolds, R, 13.2.3. In particular, if H is a Lie subgroup of G, U(H) is identified with a subalgebra of U(G), the coproduct on U(H) being the restriction of the coproduct on U(G). If H is open in G, then U(H) = U(G). If G_1, G_2 are Lie groups, U(G_1 \times G_2) is identified with U(G_1) \times U(G_2). The primitive elements of U(G) are those of T_e(G) (Differentiable and Analytic Manifolds, R, 13.5.3).

Again let ϕ:G→H\phi : G \to H be a Lie group morphism. If gr U(G) is identified TS(T_e(G)) and gr U(H) with TS(T_e(H)), then gr U(ϕ\phi) is identified with TS(T_e(ϕ\phi)) (Differentiable and Analytic Manifolds, R, 13.3.5). We apply this to the isomorphism g↦g−1g \mapsto g^{-1} of G onto G^{\vee}; then T_e(ϕ\phi) = -1 and hence

t∈Us(G)⇒t∨≡(−1)stmod  Us−1(G). t \in U_s(G) \Rightarrow t^{\vee} \equiv (-1)^s t \mod U_{s-1}(G).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.