Bourbaki

Proposition 16

Tag 0A9T, permanent. Cite it as [Bourbaki, Tag 0A9T].

Lie Groups and Lie Algebras, chapter III, § 3. Passage from a Lie group to its Lie algebra

Let G, G' be Lie groups, X a manifold of class C^r and suppose that G (resp. G') operates on X on the left (resp. right), with (gx)g′=g(xg′)(gx)g' = g(xg') for all x∈X,g∈G,g′∈G′x \in X, g \in G, g' \in G'. Let t∈T(s)(G)t \in \mathscr{T}^{(s)}(G), t′∈T(s′)(G′)t' \in \mathscr{T}^{(s')}(G'), t′′∈T(s′′)(X)t'' \in T^{(s'')}(X), with s+s′+s′′≤rs + s' + s'' \leq r. Then

(t∗t′′)∗t′=t∗(t′′∗t′). (t * t'') * t' = t * (t'' * t').
(t∗t′′)∗t′(t * t'') * t' (resp. t∗(t′′∗t′)t * (t'' * t')) is the image of t⊗t′′⊗t′t \otimes t'' \otimes t' under the mapping (g,x,g′)↦(gx)g′(g, x, g') \mapsto (gx)g' (resp. g(xg′)g(xg')) of G×X×G′G \times X \times G' into X.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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Transcribed from the printed volume. Not translated.