Library / Lie Groups and Lie Algebras / Chapter III / § 3
Proposition 19
Tag 0A9X, permanent. Cite it as [Bourbaki, Tag 0A9X].
Lie Groups and Lie Algebras, chapter III, § 3. Passage from a Lie group to its Lie algebra
Let t ∈ T ( s ) ( G ) t \in \mathscr{T}^{(s)}(G) t ∈ T ( s ) ( G ) , with s ≤ r s \leq r s ≤ r . Let f f f (resp. f ′ f' f ′ ) be a function of class C r C^r C r on X X X with values in a Hausdorff polynormed space F F F (resp. F ′ F' F ′ ). Let ( u , u ′ ) ↦ u u ′ (u, u') \mapsto uu' ( u , u ′ ) ↦ u u ′ be a continuous bilinear mapping of F × F ′ F \times F' F × F ′ into a Hausdorff polynormed space F ′ ′ F'' F ′′ , so that f f ′ ff' f f ′ is a function of class C r C^r C r on X X X with values in F ′ ′ F'' F ′′ . Let
∑ i = 1 n t i ⊗ t i ′ be the image of t in T ( s ) ( G ) ⊗ T ( s ) ( G ) under the coproduct. Then
\sum_{i=1}^n t_i \otimes t'_i \text{ be the image of } t \text{ in } \mathscr{T}^{(s)}(G) \otimes \mathscr{T}^{(s)}(G) \text{ under the coproduct. Then}
i = 1 ∑ n t i ⊗ t i ′ be the image of t in T ( s ) ( G ) ⊗ T ( s ) ( G ) under the coproduct. Then t ∗ ( f f ′ ) = ∑ i = 1 n ( t i ∗ f ) ( t i ′ ∗ f ′ ) .
t * (ff') = \sum_{i=1}^n (t_i * f)(t'_i * f').
t ∗ ( f f ′ ) = i = 1 ∑ n ( t i ∗ f ) ( t i ′ ∗ f ′ ) .
Let x ∈ X x \in X x ∈ X and let ρ ( x ) \rho(x) ρ ( x ) denote the orbital mapping of x x x . Then
⟨ ε x , t ∗ ( f f ′ ) ⟩ = ⟨ t ∨ , ( f f ′ ) ∘ ρ ( x ) ⟩ by (4) = ⟨ t ∨ , ( f ∘ ρ ( x ) ) ( f ′ ∘ ρ ( x ) ) ⟩ = ∑ i = 1 n ⟨ t i ∨ , f ∘ ρ ( x ) ⟩ ⟨ t i ′ ∨ , f ′ ∘ ρ ( x ) ⟩ = ∑ i = 1 n ⟨ ε x , t i ∗ f ⟩ ⟨ ε x , t i ′ ∗ f ′ ⟩ by (4). (Diff. & Man. Anal., R, 13.5.2)
\langle \varepsilon_x, t * (ff') \rangle = \langle t^\vee, (ff') \circ \rho(x) \rangle \quad \text{by (4)} \\
= \langle t^\vee, (f \circ \rho(x))(f' \circ \rho(x)) \rangle \\
= \sum_{i=1}^n \langle t_i^\vee, f \circ \rho(x) \rangle \langle t_{i'}^\vee, f' \circ \rho(x) \rangle \tag{Diff. \& Man. Anal., R, 13.5.2} \\
= \sum_{i=1}^n \langle \varepsilon_x, t_i * f \rangle \langle \varepsilon_x, t_i' * f' \rangle \quad \text{by (4).}
⟨ ε x , t ∗ ( f f ′ )⟩ = ⟨ t ∨ , ( f f ′ ) ∘ ρ ( x )⟩ by (4) = ⟨ t ∨ , ( f ∘ ρ ( x )) ( f ′ ∘ ρ ( x ))⟩ = i = 1 ∑ n ⟨ t i ∨ , f ∘ ρ ( x )⟩ ⟨ t i ′ ∨ , f ′ ∘ ρ ( x )⟩ = i = 1 ∑ n ⟨ ε x , t i ∗ f ⟩ ⟨ ε x , t i ′ ∗ f ′ ⟩ by (4). ( Diff. & Man. Anal., R, 13.5.2 )
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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Transcribed from the printed volume. Not translated.