Bourbaki

Proposition 52

Tag 0ABU, permanent. Cite it as [Bourbaki, Tag 0ABU].

Lie Groups and Lie Algebras, chapter III, § 3. Passage from a Lie group to its Lie algebra

Let n be an integer > 0, G an n-dimensional Lie group, U a symmetric open neighbourhood of e in G and ψ:U2→Kn\psi : U^2 \to K^n a chart of G such that ψ(e)=0\psi(e) = 0. If (x1,…,xn)(x_1, \ldots, x_n) are the coordinates of x∈ψ(U)x \in \psi(U) and (y1,…,yn)(y_1, \ldots, y_n) the coordinates of y∈ψ(U)y \in \psi(U), we denote by

m1(x1,…,xn,y1,…,yn),…,mn(x1,…,xn,y1,…,yn) m_1(x_1, \ldots, x_n, y_1, \ldots, y_n), \ldots, m_n(x_1, \ldots, x_n, y_1, \ldots, y_n)

the coordinates of ψ(ψ−1(x)−1ψ−1(y))\psi(\psi^{-1}(x)^{-1}\psi^{-1}(y)). Then, if we write, for 1≤k≤n1 \leq k \leq n,

ϖk(x1,…,xn)=Dn+1mk(x1,…,xn,x1,…,xn)dx1+⋯+D2nmk(x1,…,xn,x1,…,xn)dxn, \varpi_k(x_1, \ldots, x_n) = D_{n+1} m_k(x_1, \ldots, x_n, x_1, \ldots, x_n) dx_1 + \cdots \\ + D_{2n} m_k(x_1, \ldots, x_n, x_1, \ldots, x_n) dx_n,

the differential forms ϖk\varpi_k on ψ(U)\psi(U) are derived through ψ\psi from left invariant differential forms on G and are such that ϖk(0,…,0)=dxk\varpi_k(0, \ldots, 0) = dx_k.

We apply Lemma 2 with E=KE = K, taking ϕ(g)\phi(g) to be the coordinate of ψ(g)\psi(g) of index k. We obtain a differential form ωk\omega_k; let ϖk\varpi_k be its transform under ψ\psi. The value of ϖk\varpi_k at (x1,…,xn)(x_1, \ldots, x_n) is the differential at (x1,…,xn)(x_1, \ldots, x_n) of the function y↦mk(x1,…,xn,y1,…,yn)y \mapsto m_k(x_1, \ldots, x_n, y_1, \ldots, y_n); this value is therefore given by formula (32). It then suffices to use the conclusion to Lemma 2.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.