Bourbaki

Theorem 5

Tag 0ADF, permanent. Cite it as [Bourbaki, Tag 0ADF].

Lie Groups and Lie Algebras, chapter III, § 4. Passage from Lie algebras to Lie groups

Let G be a Lie group germ, M a manifold of class CrC^r (r≥2r \geq 2) and α\alpha a differential form of class Cr−1C^{r-1} and degree 1 on M with values in L(G)L(G), such that dα+[α]2=0d\alpha + [\alpha]^2 = 0. For all x∈Mx \in M and all g∈Gg \in G, there exists a mapping ff, defined and of class Cr−1C^{r-1} on an open neighbourhood of xx, with values in GG, such that f(x)=gf(x) = g and f−1.df=αf^{-1}.df = \alpha. Two mappings which satisfy these conditions coincide on a neighbourhood of xx.

Let x∈Mx \in M and g∈Gg \in G. By Lemma 6 (whose notation we adopt) and Differentiable and Analytic Manifolds, R, 9.3.7, there exist an open neighbourhood U of xx in M and a mapping m↦ϕ(m)=(m,f(m))m \mapsto \phi(m) = (m, f(m)) of class Cr−1C^{r-1} of U into M×GM \times G such that f(x)=gf(x) = g and ϕ∗(0)=0\phi^*(0) = 0. Then

f−1.df=f∗(ω)(§3,no. 18.9)=(pr2∘ϕ)∗(ω)(for f=pr2∘ϕ)=ϕ∗(pr1∗α−θ)(Lemma 6)=ϕ∗(pr1∗α)(for ϕ∗(θ)=0)=α(for pr1∘ϕ=IdU). f^{-1}.df = f^*(\omega) \quad (§ 3, \text{no. 18.9}) \\ = (\mathrm{pr}_2 \circ \phi)^*(\omega) \quad (\text{for } f = \mathrm{pr}_2 \circ \phi) \\ = \phi^*(\mathrm{pr}_1^*\alpha - \theta) \quad (\text{Lemma 6}) \\ = \phi^*(\mathrm{pr}_1^*\alpha) \quad (\text{for } \phi^*(\theta) = 0) \\ = \alpha \quad (\text{for } \mathrm{pr}_1 \circ \phi = \mathrm{Id}_U).

Let f′f' be a mapping of class Cr−1C^{r-1} of U into G such that f′(x)=gf'(x) = g and f′−1df′=α{f'}^{-1}df' = \alpha. By § 3, 18.9, f′−1{f'}^{-1} is locally constant and hence f′=ff' = f in a neighbourhood of xx.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.