Bourbaki

Proposition 10

Tag 0ADG, permanent. Cite it as [Bourbaki, Tag 0ADG].

Lie Groups and Lie Algebras, chapter III, § 4. Passage from Lie algebras to Lie groups

Let M be an analytic manifold, g\mathfrak{g} a complete normable Lie algebra and α\alpha an analytic differential form of degree 1 on M, with values in g\mathfrak{g}, with the following properties: (a) for all m∈Mm \in M, αm\alpha_m is an isomorphism of Tm(M)T_m(M) onto g\mathfrak{g}; (b) dα+[α]2=0d\alpha + [\alpha]^2 = 0.

Then, for all m0∈Mm_0 \in M, there exist an open neighbourhood M′M' of m0m_0 in M and a Lie group germ structure on M′M', compatible with the manifold structure on M′M', with identity element m0m_0 and with the following properties: (i) αm0\alpha_{m_0} is an isomorphism of L(M′)L(M') onto g\mathfrak{g}; (ii) the differential form m↦αm0−1∘αmm \mapsto \alpha_{m_0}^{-1} \circ \alpha_m is the left canonical differential form of M′M'. If M1′M'_1 and M2′M'_2 are two such group germs, M1′M'_1 and M2′M'_2 have a common open subgroup germ.

There exists a Lie group germ G such that L(G)=gL(G) = \mathfrak{g}. Let m0∈Mm_0 \in M. By Theorem 5, there exist an open neighbourhood M′M' of m0m_0 in M and an analytic mapping ff of M′M' into G such that f(m0)=ef(m_0) = e and f−1.df=αf^{-1}.df = \alpha. Then Tm0(f)=αm0T_{m_0}(f) = \alpha_{m_0} is an isomorphism of Tm0(M)T_{m_0}(M) onto g\mathfrak{g}; hence, shrinking M′M' and G, it can be assumed that ff is an isomorphism of the manifold M′M' onto the manifold G. We transport to M′M' the Lie group germ structure on G by means of f−1f^{-1}. Then Tm0(f)T_{m_0}(f) becomes an isomorphism of L(M′)L(M') onto L(G)=gL(G) = \mathfrak{g}, whence (i). On the other hand, if ω\omega denotes the left canonical differential form of GG, then

αm0−1∘αm=(Tm0f)−1∘(f−1.df)(m)=(Tmf)−1∘ω(f(m))∘Tmf \alpha_{m_0}^{-1} \circ \alpha_m = (\mathrm{T}_{m_0} f)^{-1} \circ (f^{-1}.df)(m) = (\mathrm{T}_m f)^{-1} \circ \omega(f(m)) \circ \mathrm{T}_m f
and hence m↦αm0−1∘αmm \mapsto \alpha_{m_0}^{-1} \circ \alpha_m is the left canonical differential form of M′M'.

Let M′′M'' be an open neighbourhood of m0m_0, with a Lie group germ structure, with identity element m0m_0 and with the analogous properties to properties (i) and (ii). Then αm0\alpha_{m_0} is an isomorphism of L(M′)L(M') onto gg and also of L(M′′)L(M'') onto gg and hence L(M′)=L(M′′)L(M') = L(M''). Therefore, shrinking M′M' and M′′M'', it can be assumed that there exists an isomorphism ϕ\phi of the group germ M′M' onto the group germ M′′M'' (no. 1, Corollary 1 to Theorem 1). Then ϕ−1.dϕ\phi^{-1}.d\phi is the canonical left differential of M′M'. On the other hand, let ψ\psi be the canonical injection of the manifold M′∩M′′M' \cap M'' into the Lie group germ M′′M''; clearly ψ−1.dψ\psi^{-1}.d\psi is a restriction of the canonical left differential of M′′M''. Hence (ψ−1.dψ)(m)=αm0−1∘αm=(ϕ−1.dϕ)(m)(\psi^{-1}.d\psi)(m) = \alpha_{m_0}^{-1} \circ \alpha_m = (\phi^{-1}.d\phi)(m) for all m∈M′∩M′′m \in M' \cap M''. Therefore ϕ\phi and ψ\psi coincide on a neighbourhood of m0m_0 (§ 3, 18.9). This proves the last assertion of the proposition.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.