Bourbaki

Proposition 8

Tag 0AHG, permanent. Cite it as [Bourbaki, Tag 0AHG].

Lie Groups and Lie Algebras, chapter III, § 7. Lie groups over an ultrametric field

Let n∈Zn \in \mathbf{Z} and hnh_n be the mapping x↦xnx \mapsto x^n of GG into GG. Let aa be a non-zero ideal of AA contained in mm, such that n∉an \notin a. Then hn∣G(a)h_n|G(a) is an isomorphism of the analytic manifold G(a)G(a) onto the analytic manifold G(na)G(na).

By definition of standard groups, hnh_n is equal on the whole of GG to the sum of an integral series with coefficients in A′A'. By § 5, formula (4), this series is of the form

hn(x)=nx+∑∣α∣≥2aαxα. h_n(x) = nx + \sum_{|\alpha| \geq 2} a_\alpha x^\alpha.
Hence, for x∈Gx \in G,
hn(nx)=n2(x+∑∣α∣≥2aαn∣α∣−2xα)=n2S(x) \begin{align*} h_n(nx) &= n^2 \left( x + \sum_{|\alpha| \geq 2} a_\alpha n^{|\alpha|-2} x^\alpha \right) \\ &= n^2 S(x) \end{align*}
where we write S(x)=x+∑∣α∣≥2aαn∣α∣−2xαS(x) = x + \sum_{|\alpha| \geq 2} a_\alpha n^{|\alpha|-2} x^\alpha. This series S(x)S(x) defines an analytic mapping, also denoted by SS, of GG into GG. By Algebra, Chapter IV, § 6, Proposition 8, there exists an integral series S′S' in rr variables with coefficients in A′A' such that S′(S(X))=S(S′(X))=XS'(S(X)) = S(S'(X)) = X. Hence SS is an isomorphism of the analytic manifold GG onto itself and, for every non-zero ideal bb of AA contained in mm, S(G(b))⊂G(b)S(G(b)) \subset G(b), S′(G(b))⊂G(b)S'(G(b)) \subset G(b) and therefore
S(G(b))=G(b). S(G(b)) = G(b).
As hn(y)=n2S(1ny)h_n(y) = n^2 S \left( \frac{1}{n} y \right) for y∈nGy \in nG, we see that hn∣nG(b)h_n|nG(b) is an isomorphism of the analytic manifold nG(b)nG(b) onto the analytic manifold n2G(b)n^2 G(b). But, as n∉an \notin a, ∣n∣>∣λ∣|n| > |\lambda| for all λ∈a\lambda \in a, hence n−1a⊂mn^{-1} a \subset m and hence aa is of the form nbnb where bb is a non-zero ideal of AA contained in mm.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.