Bourbaki

Lemma 4

Tag 0ALD, permanent. Cite it as [Bourbaki, Tag 0ALD].

Lie Groups and Lie Algebras, chapter III, § 10. The automorphism group of a Lie group

Let HH be a finite-dimensional simply connected Lie group. (i) For all u∈Aut L(H)u \in \mathrm{Aut}\, L(H), let θ(u)\theta(u) be the unique automorphism of HH such that L(θ(u))=uL(\theta(u)) = u. Then the mapping (u,g)↦θ(u)g(u, g) \mapsto \theta(u)g of (Aut L(H))×H(\mathrm{Aut}\, L(H)) \times H into HH is analytic. (ii) Let NN be a Lie subgroup of HH and Aut(H,N)\mathrm{Aut}(H, N) the set of v∈Aut Hv \in \mathrm{Aut}\, H such that v(N)=Nv(N) = N. Then 0−1(Aut(H,N))0^{-1}(\mathrm{Aut}(H, N)) is a Lie subgroup of Aut L(H)\mathrm{Aut}\, L(H). (iii) Suppose that NN is discrete and normal, so that the Lie algebra of G=H/NG = H/N is identified with L(H)L(H). For all w∈Aut Gw \in \mathrm{Aut}\, G, let η(w)\eta(w) be the unique automorphism of HH such that L(η(w))=L(w)L(\eta(w)) = L(w). Then the mapping η\eta is an isomorphism of the group Aut G\mathrm{Aut}\, G onto the group Aut(H,N)\mathrm{Aut}(H, N). To prove (i), it suffices, by Lemma 3 of no. 1, to verify that the mapping (u,g)↦θ(u)g(u, g) \mapsto \theta(u)g is analytic in a neighbourhood of (IdL(H),e)(\mathrm{Id}_{L(H)}, e). There exists an open neighbourhood B of 0 in L(H)L(H) such that ψ=exp⁡H∣B\psi = \exp_H|B is an analytic isomorphism of B onto an open neighbourhood of e in H. There exist an open neighbourhood U of IdL(H)\mathrm{Id}_{L(H)} in Aut L(H)L(H) and an open neighbourhood B′B' of 0 in L(H)L(H) such that U(B′)⊂BU(B') \subset B. Then the mapping (u,g)↦θ(u)g(u, g) \mapsto \theta(u)g of U×ψ(B′)U \times \psi(B') into H is composed of the following mappings:

the mapping (u,g)↦(u,ψ−1(g))(u, g) \mapsto (u, \psi^{-1}(g)) of U×ψ(B′)U \times \psi(B') into U×B′U \times B'; the mapping (u,x)↦u(x)(u, x) \mapsto u(x) of U×B′U \times B' into BB; the mapping y↦ψ(y)y \mapsto \psi(y) of BB into GG.

Hence this mapping is analytic.

Let pp be the canonical mapping of H into the homogeneous space H/NH/N. Then θ−1(Aut(H,N))\theta^{-1}(\mathrm{Aut}(H, N)) is the set of u∈Aut L(H)u \in \mathrm{Aut}\ L(H) such that

p(θ(u)g)=p(e),p(θ(u−1)g)=p(e) p(\theta(u)g) = p(e), \quad p(\theta(u^{-1})g) = p(e)
for all g∈Ng \in N. By § 8, no. 2, Theorem 2 and Corollary 2 to Theorem 2, this proves (ii).

Suppose that N is discrete and normal. Let w∈Aut Gw \in \mathrm{Aut}\ G. Then

L(p∘η(w))=L(η(w))=L(w)=L(w∘p) L(p \circ \eta(w)) = L(\eta(w)) = L(w) = L(w \circ p)
hence p∘η(w)=w∘pp \circ \eta(w) = w \circ p and therefore η(w)∈Aut(H,N)\eta(w) \in \mathrm{Aut}(H, N). Clearly the mapping η\eta of Aut G\mathrm{Aut}\ G into Aut(H,N)\mathrm{Aut}(H, N) is an injective homomorphism. This homomorphism is surjective because p:H→Gp : H \to G is a submersion.

Let G be a locally compact group and Γ\Gamma the automorphism group of G. Recall that a topology Tβ\mathscr{T}_\beta has been defined on Γ\Gamma (General Topology, Chapter X, § 3, no. 5). It is the coarsest topology for which the mappings v↦vv \mapsto v and v↦v−1v \mapsto v^{-1} of Γ\Gamma into Cc(G;G)C_c(G; G) (space of continuous mappings of G into G with the compact convergence topology) are continuous. The topology Tβ\mathscr{T}_\beta is compatible with the group structure on Γ\Gamma (loc. cit.). For every compact subset L of G and every neighbourhood U of eGe_G in G, let N(L,U)N(L, U) be the set of ϕ∈Γ\phi \in \Gamma such that ϕ(g)∈gU\phi(g) \in gU and ϕ−1(g)∈gU\phi^{-1}(g) \in gU for all g∈Lg \in L; then the N(L,U)N(L, U) form a fundamental system of neighbourhoods of eΓe_\Gamma. If G is generated by a compact subset C, the topology Tβ\mathscr{T}_\beta is also the coarsest topology for which the mappings v↦v∣Cv \mapsto v|C and v↦v−1∣Cv \mapsto v^{-1}|C of Γ\Gamma into Cu(C;G)C_u(C; G) are continuous (for every compact subset of G is contained in (C∪C−1)n(C \cup C^{-1})^n for sufficiently large n). If K is locally compact and V is a finite-dimensional vector space over K, the topology Tβ\mathscr{T}_\beta on GL(V)\mathbf{GL}(V) is just the usual topology.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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