Bourbaki

Corollary

Tag 0APV, permanent. Cite it as [Bourbaki, Tag 0APV].

Lie Groups and Lie Algebras, chapter V, § 2. Reflections

*Let D and D' be two lines of V and let θ\theta be a measure of the angle (D^,D′^)(\widehat{D}, \widehat{D'}). Then sD′sD=ρ2θs_{D'} s_D = \rho_{2\theta}.

We know that sD′sDs_{D'} s_D is a rotation since it is of determinant 1. Let Δ\Delta and Δ′\Delta' be two half-lines starting at the origin carried by D and D'. We have

(Δ,sD′sD^(Δ))≡(Δ,sD′^(Δ))≡(Δ^,Δ′^)+(Δ′,sD′^(Δ))≡(Δ^,Δ′^)+(sD′(Δ′),sD′^(Δ))≡(Δ^,Δ′^)−(Δ′,Δ)≡2(Δ^,Δ′^)(mod2π), \begin{align*} (\Delta, \widehat{s_{D'} s_D}(\Delta)) &\equiv (\Delta, \widehat{s_{D'}}(\Delta)) \equiv (\widehat{\Delta}, \widehat{\Delta'}) + (\Delta', \widehat{s_{D'}}(\Delta)) \\ &\equiv (\widehat{\Delta}, \widehat{\Delta'}) + (s_{D'}(\Delta'), \widehat{s_{D'}}(\Delta)) \\ &\equiv (\widehat{\Delta}, \widehat{\Delta'}) - (\Delta', \Delta) \equiv 2(\widehat{\Delta}, \widehat{\Delta'}) \pmod{2\pi}, \end{align*}
hence the corollary.

Now let Δ\Delta and Δ′\Delta' be two half-lines of V such that

Δ≠Δ′andΔ≠−Δ′, \Delta \neq \Delta' \quad \text{and} \quad \Delta \neq -\Delta',
and let s and s′s' be the orthogonal reflections with respect to the lines D and D' containing Δ\Delta and Δ′\Delta'. Let θ\theta be the principal measure of the angle (D^,D′^)(\widehat{D}, \widehat{D'}). If θ∈πQ\theta \in \pi \mathbf{Q}, denote by m the smallest integer ≥1\geq 1 such that mθ∈πZm\theta \in \pi \mathbf{Z}. If θ∉πQ\theta \notin \pi \mathbf{Q}, put m=∞m = \infty. Let W be the group generated by s and s′s'.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.