Bourbaki

Proposition 4

Tag 0B3H, permanent. Cite it as [Bourbaki, Tag 0B3H].

General Topology, chapter I, § 5. Open mappings and closed mappings

Let R be an open (resp. closed) equivalence relation on a topological space X, and f the canonical mapping X→X/RX \to X/R. Let A be a subset of X and suppose that one of the following two conditions is satisfied:

a) A is open (resp. closed) in X.

b) A is saturated with respect to R.

Then the relation RAR_A induced on A is open (resp. closed) and the canonical mapping of A/RAA/R_A onto f(A)f(A) is a homeomorphism.

Consider the commutative diagram (i) of § 3, no. 6, which gives the canonical decomposition of f∘jf \circ j. Under condition a), jj is open (resp. closed) and so is ff by hypothesis; hence f∘jf \circ j is open (resp. closed) [no. 1, Proposition 1 a)], and the result follows from Proposition 3. Under condition b) we have

A=f‾−1(f(A)), A = \overline{f}^{-1}(f(A)),
and h∘φh \circ \varphi is the mapping of AA into f(A)f(A) which agrees with ff on AA; by virtue of Proposition 2 a) of no. 1, h∘φh \circ \varphi is open (resp. closed), and the result again follows from Proposition 3, applied to h∘φh \circ \varphi.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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