Proposition 28
Tag 0BJ1, permanent. Cite it as [Bourbaki, Tag 0BJ1].
General Topology, chapter III, § 2. Subgroups, quotient groups, homomorphisms homogeneous spaces, product groups
*Let L, N be two topological groups, let be a homomorphism of L into the group of automorphisms of the (non-topological) group structure of N; and suppose that the mapping of into N is continuous. Then:
1) On the external semi-direct product S of N and L, relative to , the product of the topologies of N and L is compatible with the group structure; the canonical injections and are isomorphisms of the topological groups N and L respectively onto the subgroups and of S, and is a strict morphism of S onto L.
2) Let and be two continuous homomorphisms into a topological group G, satisfying (4); then the homomorphism
of S into G is continuous.
This is an immediate consequence of the definitions and of the properties of the product topology.
The topological group S thus defined is said to be the external topological semi-direct product of N and L (relative to σ); notice that the condition imposed on σ implies that L operates continuously on the left on N according to the external law [no. 4].
Now let G be a topological group and let N and L be two subgroups of G such that G is the semi-direct product of N and L, qua non-topological group; it is then clear that the mapping is continuous on , and that the canonical bijective homomorphism
of S onto G is continuous. But this homomorphism is not necessarily bicontinuous; when it is bicontinuous, G is said to be the topological semi-direct product of N and L. For this to be so it is necessary and sufficient that, if and are the mappings which make correspond to the unique elements and such that , then one of the mappings is continuous (in which case both are continuous). It comes to the same thing to say that the restriction to L of the canonical mapping is an isomorphism of the topological group L onto the topological group G/N.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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