Bourbaki

Example 4

Tag 0C1A, permanent. Cite it as [Bourbaki, Tag 0C1A].

General Topology, chapter IX, § 1. Generation of a uniformity by a family of pseudometrics; uniformizable spaces

\* Let X be the set of all continuous mappings of the interval [0, 1] of R\mathbf{R} into R\mathbf{R}. If for each pair of elements x,yx, y of X we put

f(x,y)=∫01∣x(t)−y(t)∣ dt, f(x, y) = \int_0^1 |x(t) - y(t)| \, dt,
then f is a pseudometric on X. \*

Remarks: 1) Example 2 above shows that a pseudometric can take the value +∞+\infty for certain pairs of elements of XX. 2) If ff is a pseudometric on XX, we can in general have f(x,y)=0f(x, y) = 0 without x=yx = y, as Example 3 above shows (cf. § 2).

From the triangle inequality it follows that if f(x,z)f(x, z) and f(y,z)f(y, z) are finite then so is f(x,y)f(x, y); moreover, in this case we have

f(x,z)≤f(y,z)+f(x,y)andf(y,z)≤f(x,z)+f(x,y), f(x, z) \leq f(y, z) + f(x, y) \quad \text{and} \quad f(y, z) \leq f(x, z) + f(x, y),
so that (I)
∣f(x,z)−f(y,z)∣≤f(x,y). |f(x, z) - f(y, z)| \leq f(x, y).

If ff is a pseudometric on XX, then so is kfkf for any finite real number k>0k > 0. If {fi}i∈I\{f_i\}_{i \in I} is any family of pseudometrics on XX, the sum ∑i∈Ifi\sum_{i \in I} f_i is defined for all x,y∈X∖Xx, y \in X \setminus X; if ff denotes the value of this sum, then ff is a pseudometric on XX. Again, the supremum of the family {fi}\{f_i\} (Chapter IV, § 5, no. 5) is a pseudometric on XX, for the relations fi(x,y)≤fi(x,z)+fi(z,y)f_i(x, y) \leq f_i(x, z) + f_i(z, y) imply

sup⁡i∈Ifi(x,y)≤sup⁡i∈I(fi(x,z)+fi(z,y))≤sup⁡i∈Ifi(x,z)+sup⁡i∈Ifi(z,y) \sup_{i \in I} f_i(x, y) \leq \sup_{i \in I} (f_i(x, z) + f_i(z, y)) \leq \sup_{i \in I} f_i(x, z) + \sup_{i \in I} f_i(z, y)
[Chapter IV, § 5, no. 7, formula (17)].

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.