Proposition 3
Tag 0CWH, permanent. Cite it as [Bourbaki, Tag 0CWH].
Commutative Algebra, chapter IX, § 2. Anneaux de Cohen
Let be a projective system of rings relative to the set of indices . Suppose that is a -ring for every and that the homomorphisms are surjective. Then is a -ring, and for every , the canonical homomorphism is surjective and induces an isomorphism of onto .
Since the mappings are surjective, the same is true of the mappings (E, III, p. 58, prop. 5). Let us show that is a -ring. Let be the length of . By prop. 2, a), the sequence of the elements of is increasing; if it is stationary, there exists an integer such that is an isomorphism of onto whenever , so that , isomorphic to , is a -ring.
It is therefore enough to consider the case where each is finite, and where the sequence tends to . Endow the ring with the trivial filtration (III, § 2, No. 1, example 5). For , let be the kernel of ; put if . Let denote the -module endowed with the filtration . It is separated and complete, for the topology defined by the filtration is the projective limit topology of the discrete topologies on the .
Let k be an integer . We have (E, III, p. 55, formula (9)). Conversely, if and if one puts , the sequence is a decreasing sequence of nonempty closed affine parts of E. Since is an artinian C-module, the intersection of the is nonempty (III, § 2, No. 7, prop. 7); for every , one has . We have therefore proved that one has for every integer . In particular the ideal of C is closed for the topology . On C, the -adic topology is finer than the topology since one has . It then follows from TG, III, p. 26, cor. 1 to prop. 10, that C is separated and complete for the -adic topology. Moreover one has and therefore the surjective homomorphism from into deduced from is an isomorphism. This shows that the ideal of C is maximal and consequently that C is a -ring. The last assertion of prop. 3 follows from prop. 2, b).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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