Bourbaki

Theorem 1

Tag 0CZX, permanent. Cite it as [Bourbaki, Tag 0CZX].

Commutative Algebra, chapter IX, Appendix 0.

Let f:A→A′f : A \to A' be a surjective local homomorphism of local rings and let B′B' be an inflation of A′A'. There exists an inflation B of A and an isomorphism of A-algebras of B⊗AA′B \otimes_A A' onto B′B'. A) Suppose that B′B' is an elementary inflation of A′A'. Let us distinguish two cases: 1) If B′B' is finite over A′A', choose an isomorphism of A′−algebrasA'-algebras φ:A′[X]/(P′)→B′\varphi : A'[X]/(P') \to B', where P′∈A′[X]P' \in A'[X] is a monic polynomial whose image is irreducible in κA′[X]\kappa_{A'}[X]. Choose a monic polynomial P∈A[X]P \in A[X] whose image in A′[X]A'[X] is P′P'. It is necessarily irreducible modulo the maximal ideal of A. Put then B=A[X]/(P)B = A[X]/(P). The A-algebra B is an elementary inflation of A and φ\varphi induces an isomorphism of A-algebras of B⊗AA′B \otimes_A A' onto B′B'. 2) If B′B' is not finite over A′A', choose an isomorphism of A′−algebrasA'-algebras ψ:A′[X]→B′\psi : A'[X] \to B'. Put B=A[X][B = A[X][. The A-algebra B is an elementary inflation of A, and B⊗AA′B \otimes_A A' is canonically isomorphic to A′[X][A'[X][. Hence ψ\psi induces an isomorphism of A-algebras of B⊗AA′B \otimes_A A' onto B′B'. B) We pass to the general case. Let (Bλ′)λ∈Λ(B'_\lambda)_{\lambda \in \Lambda} be a family of sub-A′A'-algebras of B′B' having with respect to A′A' and B′B' properties a), b), c) of Def. 2. We are going to define by transfinite induction an inductive system (B~λ,iμλ)(\tilde{B}_\lambda, i_{\mu \lambda}) indexed by Λ\Lambda of local rings and injective local homomorphisms, and isomorphisms uλ:B~λ⊗AA′→Bλ′u_\lambda : \tilde{B}_\lambda \otimes_A A' \to B'_\lambda such that, for λ≤μ\lambda \leq \mu, uμ∘(iμλ⊗IdA′)∘uλ−1u_\mu \circ (i_{\mu \lambda} \otimes \mathrm{Id}_{A'}) \circ u_\lambda^{-1} is the canonical injection of Bλ′B'_\lambda into Bμ′B'_{\mu}. If α\alpha is the smallest element of Λ\Lambda, we put B~α=A,iαα=IdA\tilde{B}_\alpha = A, i_{\alpha \alpha} = \mathrm{Id}_A and take for uαu_\alpha the canonical isomorphism A⊗AA′→A′A \otimes_A A' \to A'. Let ν∈Λ\nu \in \Lambda, and suppose that B~λ,uλ\tilde{B}_\lambda, u_\lambda and iμλi_{\mu \lambda} have been constructed when λ≤μ<ν\lambda \leq \mu < \nu. Let SνS_\nu be the set of elements ε\varepsilon of Λ\Lambda such that ε<ν\varepsilon < \nu. If SνS_\nu has no greatest element, we take for B~ν\tilde{B}_\nu the inductive limit of the B~λ\tilde{B}_\lambda for λ∈Sν\lambda \in S_\nu, for uνu_\nu the composite isomorphism B~ν⊗AA′→lim⁡(B~λ⊗AA′)→lim⁡Bλ′→Bν′\tilde{B}_\nu \otimes_A A' \to \lim (\tilde{B}_\lambda \otimes_A A') \to \lim B'_\lambda \to B'_\nu, and for iνλi_{\nu \lambda}, when λ∈Sν\lambda \in S_\nu, the canonical mapping of B~λ\tilde{B}_\lambda into B~ν\tilde{B}_\nu. If SνS_\nu has a greatest element μ\mu, then Bν′B'_\nu is an elementary inflation of Bμ′B'_{\mu}. By A), there exists an elementary inflation i_{v\mu}: \tilde{B}_{\mu} \to \tilde{B}_{v} et un isomorphisme de B~μ\tilde{B}_{\mu}-algèbres de B~v⊗B~μBμ′\tilde{B}_{v} \otimes_{\tilde{B}_{\mu}} B'_{\mu} sur Bv′B'_{v}. We take for uvu_{v} the composite isomorphism of A-algebras

B~v⊗AA′→B~v⊗B~μ(B~μ⊗AA′)→B~v⊗B~μBμ′→Bv′ \tilde{B}_{v} \otimes_{A} A' \to \tilde{B}_{v} \otimes_{\tilde{B}_{\mu}} (\tilde{B}_{\mu} \otimes_{A} A') \to \tilde{B}_{v} \otimes_{\tilde{B}_{\mu}} B'_{\mu} \to B'_{v}
and for ivλi_{v\lambda}, when λ∈Sv\lambda \in S_{v}, the homomorphism ivμ∘iμλi_{v\mu} \circ i_{\mu\lambda}.

Let us then put B=B~ωB = \tilde{B}_{\omega} and, for every λ∈Λ\lambda \in \Lambda, denote by BλB_{\lambda} the image of B~λ\tilde{B}_{\lambda} under the canonical injection B~λ→B\tilde{B}_{\lambda} \to B. The family (Bλ)λ∈Λ(B_{\lambda})_{\lambda \in \Lambda} satisfies conditions a), b), c) of Definition 2, and B is an inflation of A. On the other hand, the homomorphism uωu_{\omega} is an A'-isomorphism of B⊗AA′B \otimes_{A} A' onto B′B'.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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