Bourbaki

习题 6, § 1

标签 09OA,永久不变。引用为 [Bourbaki, Tag 09OA]。

积分, IX, p. 107

Google 翻译生成的粗略草稿,质量较低。术语依照术语表,但句子可能有误;之后会由仔细的译文取代。

设T为集合,F+(T)\mathscr{F}_+(T)的I+\mathscr{I}_+子集,I+\mathscr{I}_+的M映射为R‾+\overline{\mathbf{R}}_+。 We make the following hypotheses: a) For every f∈I+f \in \mathscr{I}_+ and every real number t≥0t \geq 0, the function t⋅ft \cdot f belongs to I+\mathscr{I}_+ and M(t⋅f)=t⋅M(f)M(t \cdot f) = t \cdot M(f). b) If ff and gg belong to I+\mathscr{I}_+, then so do f+gf + g, sup⁡(f,g)\sup(f, g) and inf⁡(f,g)\inf(f, g), and one has M(f+g)=M(f)+M(g)M(f + g) = M(f) + M(g). c) For every increasing sequence (fn)n≥1(f_n)_{n \geq 1} of elements of I+\mathscr{I}_+, the function f=sup⁡nfnf = \sup_n f_n belongs to I+\mathscr{I}_+, and M(f)=lim⁡n→∞M(fn)M(f) = \lim_{n \to \infty} M(f_n). For every function f∈F+(T)f \in \mathscr{F}_+(T), we set p(f)=inf⁡g∈I+,g≥fM(g)p(f) = \inf_{g \in \mathscr{I}_+, g \geq f} M(g). 证明 pp 是 T 上的负担(cf. Ch. IV, §1, No. 3)。 如果ff和gg属于到F+(T)\mathscr{F}_+(T)并且如果A和B是T的子集,则p(sup⁡(f,g))+p(inf⁡(f,g))≤p(f)+p(g)p(\sup(f, g)) + p(\inf(f, g)) \leq p(f) + p(g)和p(A∪B)+p(A∩B)≤p(A)+p(B)p(A \cup B) + p(A \cap B) \leq p(A) + p(B)。

解答

尚未写出解答。

被以下引用

无。

引用了

Google 翻译生成的粗略草稿,质量较低。术语依照术语表,但句子可能有误;之后会由仔细的译文取代。