Bourbaki

Exercise 6, § 3

Topological Vector Spaces, IV, p. 59

Bourbaki marks this one as harder than the rest.

a)** Let E be a (DF) space (IV, p. 57, exerc. 2), and let U be a convex set such that for every bounded, convex and balanced subset A of E, U∩AU \cap A is a neighbourhood of 0 for the topology induced on A by that of E. Show that U is a neighbourhood of 0 in A. (Let (An)(A_n) be a countable base for the canonical bornology of E (III, p. 3, def. 5). Show that, by induction we can define a sequence (λn)(\lambda_n) of numbers >0> 0 and a sequence (Vn)(V_n) of closed, convex and balanced neighbourhoods of 0 in E such that λnAn⊂13U,λnAn⊂⋂j=1∞Vj,Vn∩An⊂U\lambda_n A_n \subset \frac{1}{3} U, \lambda_n A_n \subset \bigcap_{j=1}^\infty V_j, V_n \cap A_n \subset U for every nn.

First show that if λj\lambda_j and VjV_j have been constructed for j≤nj \leq n, then we can find λn+1\lambda_{n+1} such that λn+1An+1⊂13U\lambda_{n+1} A_{n+1} \subset \frac{1}{3} U and λn+1An+1⊂Vj\lambda_{n+1} A_{n+1} \subset V_j for j≤nj \leq n. Next prove that we can find Vn+1V_{n+1} such that λjAj⊂Vn+1\lambda_j A_j \subset V_{n+1} for j≤n+1j \leq n + 1 and Vn+1∩An+1⊂UV_{n+1} \cap A_{n+1} \subset U; for this, letting A denote the convex envelope of the λjAj\lambda_j A_j for j≤n+1j \leq n + 1, show that we can take Vn+1=A+V‾V_{n+1} = \overline{A + V} for a suitable convex balanced neighbourhood V of 0; we remark that for this it is enough to show that, if B=An+1∩∁UB = A_{n+1} \cap \complement U, then 0 is not in the closure of the set B+2AB + 2A. b) Deduce from a) that if uu is a linear mapping from E into a locally convex space F, such that the restriction of uu to every bounded subset of E is continuous, then uu is continuous (cf.cf. IV, p. 50, exerc. 15).

Solution

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