Bourbaki marks this one as harder than the rest.
Let K be a non-discrete, Hausdorff, topological division ring, and let φ:K→R+ be a mapping such that φ(0)=0,φ(xy)=φ(x)φ(y) and such that if Vn denotes the set of all x∈K such that φ(x)≤1/n, the sets Vn form a fundamental system of neighbourhoods of 0 in K.
a) Show that there exists a real number a>0 such that, for all x∈K,
φ(1+x)≤a(1+φ(x)) [if not, there would exist a sequence
(xn) of points of
K such that both
(1+xn)−1 and
xn(1+xn)−1 tended to zero]. Hence show that if
ψ(x)=(φ(x))α we have
ψ(x+y)≤2sup(ψ(x),ψ(y)) for
α sufficiently small.
b) Show that if n=2p we have ψ(∑i=1nxi)≤nsup(ψ(xi)), and deduce that for every integer m>0 we have ψ(m)≤2m.
c) Deduce from b) that for every n=2p and every x∈K we have ψ((1+x)n−1)≤2n(1+ψ(x))n−1, and hence that ψ is an absolute value on K which defines the topology of K.