Lemma 3
Tag 0063, permanent. Cite it as [Bourbaki, Tag 0063].
Algebra, VIII, p. 88, § 5. Commutation
Let M be a semisimple A-module. Let B be the bicommutant of the A-module M. Then every A-submodule of M is a B-submodule of M.
Let N be an A-submodule of M. By Corollary 2 of VIII, p. 56, there exists a projector of the A-module M with image N; it belongs to . Since we have the relation for every , we obtain that N is a B-submodule of M.
Let us conclude the proof of Theorem 3. Suppose that belongs to , and let F = be a finite subset of M. Denote the element of by . The A-module is semisimple and, by Proposition 2 of VIII, p. 79, its bicommutant coincides with the homotheties of the -module . By Lemma 3, the A-submodule of is an -submodule of . Let be such that is equal to . Then coincides with on , which implies condition (D).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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