Theorem 3 (Jacobson)
Tag 00S1, permanent. Cite it as [Bourbaki, Tag 00S1].
Algebra, VIII, p. 88, § 5. Commutation
Let M be a semisimple A-module, and let be an endomorphism of the additive group M. Then belongs to the bicommutant of M if and only if it satisfies the following condition:
(D) For every finite subset F of M, there exists an element of A such that coincides with on F.
First, suppose that satisfies condition (D). Let be an element of . Let be an element of M, and apply condition (D) to the subset . There exists an element of A such that and , so that . Since is arbitrary, we have ; as this holds for all , we have .
For the converse, we use the following lemma.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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