Proposition 9
Tag 0065, permanent. Cite it as [Bourbaki, Tag 0065].
Algebra, VIII, p. 89, § 5. Commutation
Let L be a field and E a subring of End that contains the mapping for every . Denote by K the set of elements of L such that for every in L and every in E; it is a subfield of L.
Let V be a finite-dimensional linear subspace of the right K-vector space L, and let be a K-linear mapping from V to L. There exists an element of E that coincides with on V.
We view L as a left E-module. Since E contains the left multiplications , every E-submodule of L is a left ideal of the field L; the E-module L is therefore simple. Every endomorphism of the additive group of L that commutes with the is of the form with in L. Consequently, is an isomorphism from K to the opposite ring of End(L), which is a field.
The bicommutant of the E-module L therefore consists of the endomorphisms of the right K-vector space L. Let be an endomorphism of the K-vector space L whose restriction to V coincides with ; it is an element of . Let be a basis of V over K; by Theorem 3 (VIII, p. 88), there exists an element of E such that for . By linearity, it follows that for every in V.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.