Bourbaki

Corollary

Tag 00MV, permanent. Cite it as [Bourbaki, Tag 00MV].

Algebra, VIII, p. 384, § 20. Linear Representations of Algebras

a) Suppose that the field K has characteristic 0. The homomorphisms θ\theta and θK\theta_K are injective. Two semisimple A-modules of finite dimension over K are isomorphic if and only if their characters are equal.

b) Suppose that the field K is perfect of nonzero characteristic pp. Then the homomorphism θK\theta_K is injective, and the kernel of θ\theta is pRK(A)pR_K(A). Let E be a semisimple A-module of finite dimension over K. The linear form TrE_E is zero if and only if there exists an A-module F such that E is isomorphic to FpF^p.

Let SK\mathscr{S}_K be the set of classes of simple A-modules of finite dimension over K. The elements [S], where S runs through SK\mathscr{S}_K, form a basis of the Z\mathbf{Z}-module RKR_K(A), so the elements 1⊗[S]1\otimes [S] form a basis of the K-vector space K⊗ZRK(A)K\otimes_{\mathbf{Z}}R_K(A) (VIII, p. 195).

Suppose that the field K is perfect. By Proposition 6 and the corollary of VIII, p. 383, the elements θ([S])=θK(1⊗[S])=\theta ([S]) =\theta_K(1\otimes [S]) = TrS_S of A∗A^* are linearly independent over K. It follows that the homomorphism θK\theta_K is injective and that the kernel of the homomorphism θ\theta consists of the elements ∑S∈SKnS[S]\sum_{S\in\mathscr{S}_K}n_S[S] of RK(A)R_K(A) such that nS⋅1K=0n_S\cdot 1_K= 0 for every S∈SKS\in \mathscr{S}_K. The kernel of θ\theta is therefore equal to pRKpR_K(A), where pp is the characteristic of K. In particular, if K has characteristic 0, then the homomorphism θ\theta is injective.

The last assertion of a) follows from the corollary of VIII, p. 190.

Suppose that the assumptions of b) are satisfied, and let E be a semisimple A-module of finite dimension over K. If there exists an A-module F such that E is the direct sum of pp submodules isomorphic to F, then the module F is semisimple and finite-dimensional over K and we have TrE=p_E=p TrF=0_F= 0. Conversely, suppose TrE=0_E= 0. We have [E]∈pRK[E]\in pR_K(A), so the multiplicity of every simple module S∈SKS\in \mathscr{S}_K in E is a multiple of pp (VIII, p. 190, Proposition 7); we can write it as pnSp n_S with nS∈Nn_S\in \mathbf{N}. The family (nS)(n_S) has finite support. Set F=⊕S∈SKSnSF =\oplus_{S\in\mathscr{S}_K}S^{n_S}. We then have [E]=[Fp][E] = [F^p], so that E and FpF^p are isomorphic (VIII, p. 190, Corollary).

Let E be an A-module of finite dimension over K. Let a∈Aa\in A. Denote by χE(a;T)\chi_E(a; T) the determinant of the endomorphism 1E+TaE1_E+ Ta_E of the K[T]-module E[T]=K[T]⊗KEE[T] = K[T]\otimes_KE (III, §8, No. 11, p. 541). We have the relation

(10) χE(a;T)≡1+\chi_E(a; T)\equiv 1 + TrE(a)T_E(a)T (mod T2K[T]T^2K[T])

(loc. cit., formula (49)). Since this polynomial has constant term equal to 1, it is an invertible formal power series (IV, §4, No. 4, p. 30). Moreover, if

0⟶E′⟶E⟶E′′⟶0 0\longrightarrow E'\longrightarrow E\longrightarrow E''\longrightarrow 0

is an exact sequence of A-modules, all finite-dimensional over K, then we have χE(a;T)=χE′(a;T)χE′′(a,T)\chi_E(a; T) =\chi_{E'}(a; T)\chi_{E''}(a,T) (III, §8, No. 7, p. 534, formula (31)). By the definition of the Grothendieck group RK(A)R_K(A) (VIII, p. 194) and its universal property (VIII, p. 186, Proposition 4), there exists a unique homomorphism χa\chi_a from the group RK(A)R_K(A) to the multiplicative group 1 + TK[[T]] such that χa([E])=χE(a;T)\chi_a([E]) =\chi_E(a; T) for every A-module E of finite dimension over K. We deduce from formula (10) the relation

(11) χa(x)≡1+θ(x)(a)T\chi_a(x)\equiv 1 +\theta (x)(a)T (mod T2K[[T]]T^2K[[T]])

for x∈RK(A)x\in R_K(A) and a∈Aa\in A.

If E and E′E' are two A-modules of finite dimension over K with isomorphic semisimplifications, then we have χE(a;T)=χE′(a;T)\chi_E(a; T) =\chi_{E'}(a; T).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.