Corollary
Tag 00MV, permanent. Cite it as [Bourbaki, Tag 00MV].
Algebra, VIII, p. 384, § 20. Linear Representations of Algebras
a) Suppose that the field K has characteristic 0. The homomorphisms and are injective. Two semisimple A-modules of finite dimension over K are isomorphic if and only if their characters are equal.
b) Suppose that the field K is perfect of nonzero characteristic . Then the homomorphism is injective, and the kernel of is . Let E be a semisimple A-module of finite dimension over K. The linear form Tr is zero if and only if there exists an A-module F such that E is isomorphic to .
Let be the set of classes of simple A-modules of finite dimension over K. The elements [S], where S runs through , form a basis of the -module (A), so the elements form a basis of the K-vector space (VIII, p. 195).
Suppose that the field K is perfect. By Proposition 6 and the corollary of VIII, p. 383, the elements Tr of are linearly independent over K. It follows that the homomorphism is injective and that the kernel of the homomorphism consists of the elements of such that for every . The kernel of is therefore equal to (A), where is the characteristic of K. In particular, if K has characteristic 0, then the homomorphism is injective.
The last assertion of a) follows from the corollary of VIII, p. 190.
Suppose that the assumptions of b) are satisfied, and let E be a semisimple A-module of finite dimension over K. If there exists an A-module F such that E is the direct sum of submodules isomorphic to F, then the module F is semisimple and finite-dimensional over K and we have Tr Tr. Conversely, suppose Tr. We have (A), so the multiplicity of every simple module in E is a multiple of (VIII, p. 190, Proposition 7); we can write it as with . The family has finite support. Set . We then have , so that E and are isomorphic (VIII, p. 190, Corollary).
Let E be an A-module of finite dimension over K. Let . Denote by the determinant of the endomorphism of the K[T]-module (III, §8, No. 11, p. 541). We have the relation
(10) Tr (mod )
(loc. cit., formula (49)). Since this polynomial has constant term equal to 1, it is an invertible formal power series (IV, §4, No. 4, p. 30). Moreover, if
is an exact sequence of A-modules, all finite-dimensional over K, then we have (III, §8, No. 7, p. 534, formula (31)). By the definition of the Grothendieck group (VIII, p. 194) and its universal property (VIII, p. 186, Proposition 4), there exists a unique homomorphism from the group to the multiplicative group 1 + TK[[T]] such that for every A-module E of finite dimension over K. We deduce from formula (10) the relation
(11) (mod )
for and .
If E and are two A-modules of finite dimension over K with isomorphic semisimplifications, then we have .
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.