Bourbaki

Corollary

Tag 00R1, permanent. Cite it as [Bourbaki, Tag 00R1].

Algebra, VIII, p. 81, § 5. Commutation

A generating A-module is faithful.

Let a∈Aa\in A satisfy aM=0aM = 0. Using the implication (i) ⇒\Rightarrow (iv) of Theorem 1, we obtain aAs=0aA_s= 0, and therefore a=0a= 0. The corollary follows (II, §1, No. 12, p. 219).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.