Bourbaki

Proposition 2

Tag 00YU, permanent. Cite it as [Bourbaki, Tag 00YU].

Lie Groups and Lie Algebras, chapter VIII, § 2. Root system of a split semi-simple Lie algebra

Let α,β∈R\alpha , \beta \in R.

(i) β(Hα)∈Z\beta (H_{\alpha})\in \mathbf{Z}.

(ii) If Φ\Phi denotes the Killing form of g,Φ(Hα,Hβ)∈Z\mathfrak{g},\Phi (H_{\alpha}, H_{\beta})\in \mathbf{Z}.

Let XαX_{\alpha} be a non-zero element of gα\mathfrak{g}^{\alpha}, and let ρ\rho be the representation of sl(2,k)\mathfrak{s}\mathfrak{l}(2, k) on g\mathfrak{g} associated to XαX_{\alpha}. The eigenvalues of ρ(H)\rho (H) are 0 and the β(Hα)\beta (H_{\alpha}) for β∈R\beta \in R. Hence (i) follows from §1, no. 2, Cor. of Prop. 2. Assertion (ii) follows from (i) and the Cor. of Th. 1. Q.E.D.

Let α∈R,Xα\alpha \in R,X_{\alpha} a non-zero element of gα,X−α\mathfrak{g}^{\alpha},X_{-\alpha} the element of g−α\mathfrak{g}^{-\alpha} such that [Xα,X−α]=−Hα[X_{\alpha}, X_{-\alpha}] =-H_{\alpha}, and ρ\rho the representation of sl(2,k)\mathfrak{s}\mathfrak{l}(2, k) on g\mathfrak{g} associated to XαX_{\alpha}. Let π\pi be the representation of SL(2,k)\mathbf{S}\mathbf{L}(2, k) on g\mathfrak{g} compatible with ρ(\rho (§1, no. 4, Th. 2). Since ad XαX_{\alpha} is nilpotent (Chap. VII, §1, no. 3, Prop. 10 (iv)), π(eX+)=eadXα\pi (e^{X_+}) =e^{adX_{\alpha}} is an elementary automorphism of g\mathfrak{g}. Similarly, π(eX−)=\pi (e^{X_-}) = eadX−αe^{adX_{-\alpha}} is an elementary automorphism of g\mathfrak{g}. Hence π(SL(2,k))⊂\pi (\mathbf{S}\mathbf{L}(2, k))\subset Aute(g)_e(\mathfrak{g}). We make use of the notation θ(t)\theta (t) of §1, no. 5. For t∈k∗t\in k^*, put

θα(t)=π(θ(t))=eadtXαeadt−1X−αeadtXα(1) \theta_{\alpha}(t) =\pi (\theta (t)) =e^{adtX_{\alpha}}e^{adt^{-1}X_{-\alpha}}e^{adtX_{\alpha}} \tag{1}

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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