Let α,β∈R.
(i) β(Hα)∈Z.
(ii) If Φ denotes the Killing form of g,Φ(Hα,Hβ)∈Z.
Let Xα be a non-zero element of gα, and let ρ be the representation of sl(2,k) on g associated to Xα. The eigenvalues of ρ(H) are 0 and the β(Hα) for β∈R. Hence (i) follows from §1, no. 2, Cor. of Prop. 2. Assertion (ii) follows from (i) and the Cor. of Th. 1. Q.E.D.
Let α∈R,Xα a non-zero element of gα,X−α the element of g−α such that [Xα,X−α]=−Hα, and ρ the representation of sl(2,k) on g associated to Xα. Let π be the representation of SL(2,k) on g compatible with ρ(§1, no. 4, Th. 2). Since ad Xα is nilpotent (Chap. VII, §1, no. 3, Prop. 10 (iv)), π(eX+)=eadXα is an elementary automorphism of g. Similarly, π(eX−)= eadX−α is an elementary automorphism of g. Hence π(SL(2,k))⊂ Aute(g). We make use of the notation θ(t) of §1, no. 5. For t∈k∗, put
θα(t)=π(θ(t))=eadtXαeadt−1X−αeadtXα(1)
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.