Bourbaki

Proposition 3

Tag 013K, permanent. Cite it as [Bourbaki, Tag 013K].

Lie Groups and Lie Algebras, chapter VIII, § 7. Finite dimensional modules over a split semi-simple Lie algebra

Let V be a finite dimensional g\mathfrak{g}-module and X\mathscr{X} its set of weights. Let λ∈X,α∈R\lambda \in \mathscr{X},\alpha \in R, I the set of t∈Zt\in \mathbf{Z} such that λ+tα∈X,p\lambda +t\alpha \in \mathscr{X},p (resp. −q-q) the largest (resp. smallest) element of I. Let mtm_t be the multiplicity of λ+tα\lambda +t\alpha.

(i) I = −q,p-q, p and q−p=λ(Hα)q-p=\lambda (H_{\alpha}).

(ii) For any integer u∈0,p+q,λ+(p−u)αu\in 0, p+q,\lambda + (p-u)\alpha and λ+(−q+u)α\lambda + (-q+u)\alpha are conjugate under sαs_{\alpha}, and m−q+u=mp−um_{-q+u}=m_{p-u}.

(iii) If t∈Zt\in \mathbf{Z} and t<(p−q)/2t <(p-q)/2, (Xα)V(X_{\alpha})_V maps Vλ+tαV^{\lambda+t\alpha} injectively into Vλ+(t+1)αV^{\lambda+(t+1)\alpha}.

(iv) The function t→mtt \rightarrow m_t is increasing on −q,(p−q)/2-q,(p-q)/2 and decreasing on (p−q)/2,p(p-q)/2, p.

Let α∈B\alpha \in B. Give V the sl(2,k\mathfrak{s}\mathfrak{l}(2, k)-module structure defined by the elements Xα,X−α,HαX_{\alpha}, X_{-\alpha}, H_{\alpha} of g\mathfrak{g}. Every non-zero element of Vλ+pαV^{\lambda+p\alpha} is then primitive. Consequently, (λ+pα)(Hα)≥0(\lambda +p\alpha )(H_{\alpha})\geq 0 and (X−α)rVλ+pα≠0(X_{-\alpha})^rV^{\lambda+p\alpha}\not= 0 for

0≤r≤(λ+pα)(Hα)=λ(Hα)+2p 0\leq r\leq (\lambda +p\alpha )(H_{\alpha}) =\lambda (H_{\alpha}) + 2p

(§1, no. 2, Prop. 2). It follows that Vλ+tα≠0V^{\lambda+t\alpha}\not= 0 for p≥t≥p−(λ(Hα)+2p)p\geq t\geq p-(\lambda (H_{\alpha}) + 2p), so p+q≥λ(Hα)+2pp+q\geq \lambda (H_{\alpha}) + 2p. Applying this result to −α-\alpha gives

p+q≥λ(H−α)+2q=−λ(Hα)+2q p+q\geq \lambda (H_{-\alpha}) + 2q=-\lambda (H_{\alpha}) + 2q

Hence q−p=λ(Hα)q-p=\lambda (H_{\alpha}) and λ+tα∈X\lambda +t\alpha \in \mathscr{X} for p≥t≥−qp\geq t\geq -q, which proves (i).

We have sα(α)=−αs_{\alpha}(\alpha ) =-\alpha, and sα(μ)∈μ+kαs_{\alpha}(\mu)\in \mu+k\alpha for all μ∈h∗\mu\in \mathfrak{h}^*. Since W leaves X\mathscr{X} stable (Cor. 2 of Prop. 22),sα,s_{\alpha} leaves {λ−qα,λ−qα+α,...,λ+pα}\{\lambda -q\alpha , \lambda -q\alpha +\alpha , . . . , \lambda +p\alpha \} stable and takes λ−qα+uα\lambda -q\alpha +u\alpha to λ+pα−uα\lambda +p\alpha -u\alpha for all u∈ku\in k. Using Cor. 2 of Prop. 2 again, we see that m−q+u=mp−um_{-q+u}=m_{p-u} for every integer u∈0,p+qu\in 0, p+q. This proves (ii).

By §1, Cor. of Prop. 2,(Xα)V∣Vλ+tα2, (X_{\alpha})_V|V^{\lambda+t\alpha} is injective for t<(p−q)/2t <(p-q)/2. Now (Xα)V(X_{\alpha})_V maps Vλ+tαV^{\lambda+t\alpha} to Vλ+(t+1)αV^{\lambda+(t+1)\alpha}. Hence mt+1≥mtm_{t+1}\geq m_t for t<(p−q)/2t <(p-q)/2. Changing α\alpha to −α-\alpha, we see that mt+1≤mtm_{t+1}\leq m_t for t>(p−q)/2t >(p-q)/2. This proves (iii) and (iv).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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