Proposition 3
Tag 01HH, permanent. Cite it as [Bourbaki, Tag 01HH].
Lie Groups and Lie Algebras, chapter IX, § 9. Compact Lie groups operating on manifolds
Let A be a compact subset of X. The set of morphisms that are embeddings in the neighbourhood of A is open in in the topology of compact -convergence (§ 6, no. 4).
Clearly, it suffices to prove the proposition for .
a) We show first that the subset J of consisting of the morphisms that are immersions at every point of A is open. Consider the map such that Differentiable and Analytic Manifolds, Results, 12.1).
By definition of the topology on (X;Y), the map from to is continuous; it now follows from General Topology, Chap. X, §3, no. 4, Th. 3, that is continuous.
On the other hand, let M be the set of jets in whose tangent map Differentiable and Analytic Manifolds, Results, 12.3.4) is injective. The set M is open in ; indeed, it suffices to verify this assertion when X is an open subset of a finite dimensional vector space E, and Y is an open subset of a Banach space F; we are then reduced (Differentiable and Analytic Manifolds, Results, 12.3.1) to proving that the set of injective continuous linear maps is open in (E;F), which follows from Spectral Theory, Chap. III, §2, no. 7, Prop. 16.
We conclude from the preceding that the set is open in , hence that its complement is closed. Since A is compact, the projection pr is a proper morphism, hence closed; consequently, the set J, which is equal to -- pr, is open in .
b) Let H be the subset of consisting of the elements such that . It is clear that H contains , where denotes the diagonal in the product ; we show that -- is closed in . Since is the complement in J of the image of under the proper projection pr, this will imply the proposition.
The topology of being finer than the topology of compact convergence, the map from to Y is continuous (General Topology, Chap. X, §3, no. 4, Cor. 1 of Th. 3); it follows that H is closed in . Hence, it suffices to show that is open in H, in other words, that for all and all there exists a neighbourhood of in J and a neighbourhood B of in X such that, for any morphism in , the restriction of to is injective.
Thus, the proposition follows from the following lemma:
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
Cited by
Cites
- Spectral Theory, Chap. III, §2, no. 7, Prop. 16 not in this corpus: TS III
- § 6, no. 4
- General Topology, Chap. X, §3, no. 4, Th. 3 not in this corpus
- General Topology, Chap. X, §3, no. 4, Cor. 1 of Th. 3 not in this corpus