Lemma 5
Tag 01HS, permanent. Cite it as [Bourbaki, Tag 01HS].
Lie Groups and Lie Algebras, chapter IX, § 9. Compact Lie groups operating on manifolds
Let Z be a separated manifold of class , equipped with a law of left operation of class , and a morphism (of class ) compatible with the operations of G. Let be a point of Z, and . Assume that is étale at , and that the fixer of in G is equal to the fixer of . Then, there exists an open neighbourhood of the orbit , stable under G, such that induces an isomorphism from onto an open subset of X.
Since is compatible with the operations of G, it is étale at every point of ; since the canonical map is a homeomorphism, so is the map from to induced by . Hence, it follows from Prop. 2 of no. 1 that there exists an open neighbourhood U of in Z such that induces an open embedding of U into X.
Since G operates properly on X, there exists an open neighbourhood V of and a compact subset K of G such that for General Topology, Chap. III, §4, no. 4, Prop. 7); in particular, . The set of points such that is open in Z: indeed, Z-- is the image of the closed set -- under the proper projection pr. Put ; this is an open subset of Z, containing , and satisfying the following conditions:
(i) KW , and in particular ;
(ii) .
Put GW and consider the restriction of to . This is an étale morphism, since every point of is conjugate under G to a point of U. We show that it is injective: let in G and in W be such that . Put ; then , so by (ii). But and belong to U by (i); thus, because the restriction of to V is injective, so . Hence, the restriction of to is injective, and consequently (Differentiable and Analytic Manifolds, Results, 5.7.8) is an isomorphism onto an open submanifold of X, which completes the proof.
Under the conditions of Prop. 6, the image of is an open neighbourhood T of the orbit A of , equipped with the structure of vector bundle with base A, for which the zero section is the orbit A itself. Such a neighbourhood is called a linear tube (around the orbit in question). For each point , the fibre of this vector bundle is a submanifold of X, stable under the fixer of , and such that the morphism from to X that maps the class of to induces a morphism of class from to T. Then is said to be the transversal at of the tube T. We remark that the tangent space at of is canonically isomorphic to and that it is a complement of in ; thus, the vector bundle T with base A is canonically isomorphic to the normal bundle of A in X (Differentiable and Analytic Manifolds, Results, 8.1.3).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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