Bourbaki

Proposition 1

Tag 01IS, permanent. Cite it as [Bourbaki, Tag 01IS].

Lie Groups and Lie Algebras, chapter IX, Appendix 2. Representations of real, complex or quaternionic type

Let A be an R\mathbf{R}-algebra (associative and unital) and V a finite dimensional simple A-module over R\mathbf{R}. Then, we must be in one of the following three situations:

α)\alpha ) The commutant of V (Algebra, Chap. VIII, § 5, no. 1) is isomorphic to R\mathbf{R}, and the A(C)A_{(\mathbf{C})}-module V(C)V_{(\mathbf{C})} is simple;

β)\beta ) the commutant of V is isomorphic to C\mathbf{C}; the A(C)A_{(\mathbf{C})}-module V(C)V_{(\mathbf{C})} is the direct sum of two non-isomorphic simple A(C)A_{(\mathbf{C})}-submodules which are interchanged by σ⊗1V\sigma \otimes 1_V;

γ)\gamma ) the commutant of V is isomorphic to H\mathbf{H}; the A(C)A_{(\mathbf{C})}-module V(C)V_{(\mathbf{C})} is the direct sum of two isomorphic simple A(C)A_{(\mathbf{C})}-submodules that are interchanged by σ⊗1V\sigma \otimes 1_V.

The commutant E of V is a field, a finite extension of R(\mathbf{R}(Algebra, Chap. VIII, §3, no. 2, Prop. 2), hence isomorphic to R,C\mathbf{R},\mathbf{C} or H(\mathbf{H}(Algebra, Chap. VIII, §15). The A(C)A_{(\mathbf{C})}-module V(C)V_{(\mathbf{C})} is semi-simple (Algebra, Chap. VIII, §11, no. 4), and its commutant can be identified with C⊗RE(\mathbf{C}\otimes_{\mathbf{R}}E (Algebra, Chap. VIII, §11, no. 2, Lemma 1).

If E is isomorphic to R\mathbf{R}, the commutant of V(C)V_{(\mathbf{C})} is isomorphic to C\mathbf{C}, and V(C)V_{(\mathbf{C})} is a simple A(C)A_{(\mathbf{C})}-module (Algebra, Chap. VIII, §11, no. 4).

If E is not isomorphic to R\mathbf{R}, it contains a field isomorphic to C\mathbf{C}; it follows that V has an A(C)A_{(\mathbf{C})}-module structure, denoted by VcV^c. Then VcV^c is a simple A(C)A_{(\mathbf{C})}-module, and the C\mathbf{C}-linear map ψ:V(C)→Vc⊕V‾c\psi : V_{(\mathbf{C})}\rightarrow V^c\oplus \overline{V}^c such that ψ(α⊗v)=\psi (\alpha \otimes v) = (αv,αv‾)(\alpha v,\overline{\alpha v}) for α∈C,v∈V\alpha \in \mathbf{C},v\in V, is an isomorphism (Algebra, Chap. V, §10, no. 4, Prop. 8). Moreover, σ⊗1V\sigma \otimes 1_V corresponds under this isomorphism to the R\mathbf{R}-automorphism (v,v′)→(v′,v)(v, v') \rightarrow (v', v) of Vc⊕V‾cV^c\oplus \overline{V}^c, and hence interchanges the two A(C)A_{(\mathbf{C})}-submodules ψ−1(Vc)\psi^{-1}(V^c) and ψ−1(Vc)\psi^{-1}(V^c).

The commutant E(C)E_{(\mathbf{C})} of V(C)V_{(\mathbf{C})} thus contains C×C\mathbf{C}\times \mathbf{C}, operating by homotheties on Vc⊕V‾cV^c\oplus \overline{V}^c. There is no isomorphism of A(C)A_{(\mathbf{C})}-modules from VcV^c to V‾c\overline{V}^c if and only if E(C)E_{(\mathbf{C})} reduces to C×C\mathbf{C}\times \mathbf{C}, that is, if E is isomorphic to C\mathbf{C}. This completes the proof.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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