Bourbaki

Exercise 12, § 8

Tag 01KW, permanent. Cite it as [Bourbaki, Tag 01KW].

Lie Groups and Lie Algebras, VIII, 251

Bourbaki marks this one as harder than the rest.

a) Let λ,μ∈h∗\lambda , \mu\in \mathfrak{h}^*. Every non-zero g\mathfrak{g}-homomorphism from Z(μ)Z(\mu) to Z(λ)Z(\lambda ) is injective. (Use Prop. 6 of no. 6.) b) Let r∈N,Ar\in \mathbf{N}, A a finite subset of Nr,m=\mathbf{N}^r,m= Card(A). For all ξ∈Nr\xi \in \mathbf{N}^r, let s(ξ)s(\xi ) be the sum of the coordinates of ξ\xi, and PA(ξ)\mathfrak{P}_A(\xi ) the number of families (nα)α∈A(n_{\alpha})_{\alpha\in A} of integers ≥0\geq 0 such that ξ=∑α∈Anαα\xi =\sum_{\alpha\in A}n_{\alpha}\alpha. Then PA(ξ)≤(s(ξ)+1)m\mathfrak{P}_A(\xi )\leq (s(\xi ) + 1)^m for all ξ∈Nr\xi \in \mathbf{N}^r. (Argue by induction on m.m.)

c) Let λ,μ∈h∗\lambda , \mu\in \mathfrak{h}^*. Show that dim Homg(Z(μ),Z(λ))≤1_{\mathfrak{g}}(Z(\mu),Z(\lambda ))\leq 1. (Let φ1\varphi_1 and φ2\varphi_2 be non-zero g\mathfrak{g}-homomorphisms from Z(μ)Z(\mu) to Z(λ)Z(\lambda ). If Im(φ1\varphi_1) == Im(φ2\varphi_2),φ1,\varphi_1 and φ2\varphi_2 are linearly dependent by Prop. 1 (iii) of §6. Assume that Im(φ1\varphi_1)≠\not= Im(φ2\varphi_2). If Z(μ)Z(\mu) is simple, the sum Im(φ1\varphi_1) ++ Im(φ2\varphi_2) is direct; deduce that P(ξ+λ−μ)≥2P(ξ)\mathfrak{P}(\xi +\lambda -\mu)\geq 2\mathfrak{P}(\xi ) for all ξ∈h∗\xi \in \mathfrak{h}^*, contradicting bb). In the general case, use Exerc. 11.)

When dim Homg(Z(μ),Z(λ))=1_{\mathfrak{g}}(Z(\mu),Z(\lambda )) = 1, write Z(μ)⊂Z(λ)Z(\mu)\subset Z(\lambda ) by abuse of notation. d) Let ν∈h∗\nu \in \mathfrak{h}^*. The set of λ∈h∗\lambda \in \mathfrak{h}^* such that Z(λ−ν)⊂Z(λ)Z(\lambda -\nu )\subset Z(\lambda ) is closed in h∗\mathfrak{h}^* in the Zariski topology.

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